1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution
=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution
2) Molarity = M = number of moles of solute / liters of solution
=> calculate the number of moles of 8.9 grams of NaCl
3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol
4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol
5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M
Answer: 0.152 M
Answer:density
Explanation:
it’s how’s how dens the ball is
Answer:
Nucleus,mitochondria,& cell membrane
Answer:
I would recommend them becoming an Analytical Chemist because Analytical Chemists examine and identify various elements and compounds to find out the composition, structure, and nature of substances and they determine the concentration of chemical pollutants in soil, water,and air. I would recommend taking inorganic, organic, analytical, and physical chemistry as well as computer science, physics, and environmental science
Answer:
The isotope notation for an ion of silver-109 with a charge of positive 1 is
.
Explanation:
The elements with same atomic number with different mass numbers are called isotopes.
The isotopes of silver is as follows.

From the above two isotopes have same atomic number and different mass number.
From the given,the isotope notation for an ion of silver-109 with a charge of positive 1
It can be represented is as follows.

General representation of isotope is as in attachment.