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Gwar [14]
3 years ago
7

Nombre del siguiente compuesto CH³-(CH³)³-OH

Chemistry
2 answers:
kaheart [24]3 years ago
7 0

Answer:Aceite mineral nieblas · Acetaldehído CH3CHO; Acetato de Amilo (n) CH3 COOC5H11 ... Anisidina (isómeros o y p) NH2C6H4OCH3; Antimonio Compuestos Sb; ANTU ... PbHAsO4 Pb(H2AsO4)2 Pb2As2O7; Azinphos-metil C10H12N3O3PS2 ... Dinitro-o-cresol CH3-C6H2(OH)(NO2)2; Dinitrotolueno 2,4-(NO2)2C6H3CH3 ...

Explanation:

kotykmax [81]3 years ago
4 0

Answer:

Nombre Químico

Explanation:

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Anna [14]

Answer:

Your correct.

Explanation:

5 0
3 years ago
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A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​
masha68 [24]

The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

45% complete, 55% remains

A = 0.55

Ao = 1

Input the value :

ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

k = 9.2 x 10⁻³ s⁻¹

The half life :

t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

3 0
2 years ago
Bubba falls out of a plane flying over his peanut field. What will bubba speed be after falling for 8 seconds?
chubhunter [2.5K]

Variables we know:

t = 8 seconds

Vi = 0 m/s

g = -9.81

Δy = ?

Vf = ?

Equation we will be using to solve for Vf: Vf = Vi + gt

Steps to solve:

Vf = (0) + (-9.81)(8)

Vf = -78.48 m/s

Hope this helps!! :)

5 0
3 years ago
Read 2 more answers
Name the molecule when potassium reacts with chlorine?
Dominik [7]

Answer: Potassium Chloride

Explanation:

4 0
3 years ago
As a pendulum swings from its highest to its lowest position along an arc, what happens to its kinetic energy and potential ener
lara31 [8.8K]

C.

Explanation:

As a pendulum swings from its highest to its lowest position along an arc, what happens to its kinetic energy and potential energy? The potential energy decreases while the kinetic energy increases.

4 0
2 years ago
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