Answer:
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Answer:
9.24% the percent of Mg in the mixture.
Explanation:
Mass of silver bromide = 1.1739 g
Moles of silver bromide = 
1 mole of AgBr has 1 mole of bromine atom.Then 0.006244 moles AgBr has 0.006244 mole bromine atom.
Moles of bromine atoms = 0.006244 moles
Magnesium bromide has 2 moles of bromine atom.Then 0.006244 moles of bromine atoms will be in :

Magnesium bromide has 1 mole magnesium atom, then 0.003122 moles of magnesium bromide will have :
magnesium atom
Mass of 0.003122 moles of magnesium :
0.003122 mol × 24 g/mol = 0.07493 g
Mass of the sample = 0.8107 g
Percentage of magnesium in the sample ;

9.24% the percent of Mg in the mixture.
Answer:
2.3 Work with the numerator first: 165 mg is 0.165 g. ... 2.9 (a) 1 mg Mo 1 10 3 g
Explanation:
im pretty sure this is the answer
I'm not positive about this answer but I think it's may be Northeast