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3 years ago

Write 420 as a product 9f prime numbers

Mathematics

1 answer:

stich3 [128]3 years ago

5 0

Answer:

2, 2, 3, 5, 7 that is the farthest you can go

Step-by-step explanation:

2,2,3,5,7 prime factorization of 420 but impossible to get 9 factors

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1 2 3 4 5 6 7 8 9 10

gayaneshka [121]

Answer:

The 8 should have remained positive.

Step-by-step explanation:

8-(-2)=8+2=10

Two negatives make a positive so 8-(-2) will turn into 8+2.

Laura was wrong because she thought the 8 turned to a negative but that makes no sense.

8 0

3 years ago

Please help. Don’t understand this math problem. I’ll mark you as brainliest if correct!

Tanya [424]

Answer:

I believe it is B

Step-by-step explanation:

plug in 4 where t is

3 0

3 years ago

Two people are standing on opposite sides of a hill. Person A makes an angle of elevation of 65° with the top of the hill and pe

8090 [49]

Answer:

Option 3. 71 ft. is the distance between B and top of the hill.

Step-by-step explanation:

Let the height of the hill is h ft and the distance of A from the hill be x ft and distance from B to hill is y.

It is given distance between A and B is 45 ft. ∠BAO = 65° and ∠ABO = 80°.

We have to find the distance of B from the top of the hill.

Now from ΔACO $tan 65 = \frac{h}{45-x} = 2.14$

$h=2.14(45-x)$

From ΔBCO $tan80 = \frac{h}{x} = 5.67$

h = 5.67x

Now h = 5.67x = 2.14(45-x)

5.67x = 96.3 - 2.14x

2.14x + 5.67x = 96.3

7.81x = 96.3

x = 96.3/7.81 = 12.33 ft

Therefore $cos80 = \frac{x}{OB}$

$0.174 = \frac{12.33}{OB}$

$OB = \frac{12.33}{.174}=70.86=71ft.$

Therefore 71 ft is the distance between B and the top of the hill.

3 0

3 years ago

16-2<5<br>solveeeeee itttttt

Licemer1 [7]

$b-2$

Therefore, the answer is b < 7.

4 0

3 years ago

What is the value of h when the function is converted to vertex form?

Dmitrij [34]

Answer: The value of 'h' is 3.

Step-by-step explanation: Given that the vertex form of a function is given by

$g(x)=a(x-h)^2+k~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of 'h' when the following function is converted to the vertex form.

$g(x)=x^2-6x+14~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (ii), we have

$g(x)=x^2-6x+14\\\\\Rightarrow g(x)=x^2-2\times x\times 3+3^2-3^2+14\\\\\Rightarrow g(x)=(x-3)^2-9+14\\\\\Rightarrow G(x)=(x-3)^2+5.$

Comparing it with the vertex form (i), we get

$h=3.$

Thus, the value of 'h' is 3.

4 0

3 years ago

Write 420 as a product 9f prime numbers​

Write 420 as a product 9f prime numbers