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steposvetlana [31]

4 years ago

7

By what percent must one increase the tension in a guitar string to change the speed of waves on the string from 301 m/s to 343

m/s?

1 answer:

garri49 [273]4 years ago

7 0

Answer:

29.8 %

Explanation:

You might be interested in

Homes are often insulated with fiberglass insulation in their walls and ceiling. The thermal conductivity of fiberglass is 0.040

Murljashka [212]

Answer:

2.866 x 10^8 J

Explanation:

Thermal conductivity, K = 0.040 W/m^2 k

Area of the wall, A = 470 m^2

Thickness, d = 17 cm = 0.17 m

difference in temperature, ΔT = 30° C

The rate of heat flow is H.

Time, t = 1 day = 1 x 24 x 60 x 60 second = 86400 second

By use of formula of heat flow

$H=\frac{K A \Delta T}{d}t$

$H=\frac{0.040 \times 470 \times 30}{0.17}\times 86400$

H = 2.866 x 10^8 J

3 0

4 years ago

A sprinter begins from rest and accelerates at the rate of 2 m/s^2 for 200 m.

Elanso [62]

Answer:

a. 28.28

B.14.4

C.14.4

Explanation:

A. v^2=u^ + 2as

v^2=0^2 + 2*2*200

B. v=u+at

t=v-u/a

C. V+u/2

5 0

3 years ago

An object on Earth weighs 600 N and on Mars 100 N. If its mass on Earth is approximately 60 kg what is the mass of the object on

Deffense [45]

<u>Answer:</u>

I think its

<em>10 kg</em>

plzz plzz plzz. mark as brainliest

6 0

3 years ago

Chapter 38, Problem 001

Norma-Jean [14]

Answer:

a) $\lambda=2.95x10^{-6}m$

b) infrared region

Explanation:

Photon energy is the "energy carried by a single photon. This amount of energy is directly proportional to the photon's electromagnetic frequency and is inversely proportional to the wavelength. If we have higher the photon's frequency then we have higher its energy. Equivalently, with longer the photon's wavelength, we have lower energy".

Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

$E=hf$

Where h is the Planck's Constant. By the other hand the know that $c=f\lambda$ and if we solve for f we have:

$f=\frac{c}{\lambda}$

If we replace the last equation into the E formula we got:

$E=h\frac{c}{\lambda}$

And if we solve for $\lambda$ we got:

$\lambda =\frac{hc}{E}$

Using the value of the constant $h=4.136x10^{-15} eVs$ we have this:

$\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m$

$\lambda=2.95x10^{-6}m$

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of $10^{-6}m$

4 0

3 years ago

Over the time interval after a difference in potential is applied between the ends of a wire, what would happen to the drift vel

Dmitrij [34]

The the drift velocity of the electrons is determined by atom vibrations in the crystal lattice.

<h3>How to explain the information?</h3>

Assume we could increase the average time between collisions in a typical metal to get to a limit of zero resistance. The free electrons would therefore be continuously accelerated by a constant applied voltage, according to the classical paradigm of conduction. Both the current and the drift speed would gradually pick up over time.

Although it is not the scenario implied by the question, it is possible to switch to zero resistance by using a superconducting wire instead of the usual metal. In this scenario, the maximum current is constrained, the drift velocity of the electrons is determined by atom vibrations in the crystal lattice, and it is difficult to produce a potential difference across the superconductor.

Learn more about electrons in:

brainly.com/question/860094

#SPJ4

5 0

2 years ago