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Nimfa-mama [501]
3 years ago
14

The image below shows four points on the orbit of a comet around the Sun.

Physics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer:

<u>Point </u><u>A</u>

Explanation:

And the strongest force of gravity is point C

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Models of four atoms are shown as figures A, B, C, and D. Which two atoms represent isotopes of the same element?
timurjin [86]
C and d have the same amount of protons and electrons
3 0
3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 5.5 m from the center of the ride. Then the operator turns on the rid
bixtya [17]

Answer:

u_{s}=0.56

Explanation:

For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force

F_{s.max}=\frac{mv^2}{r} \\

Where the r is the radius of merry-go-round and v is the tangential speed

but

F_{s.max}=u_{s}F_{N}=u_{s}mg

So we have

u_{s}mg=\frac{mv^2}{r}\\ u_{s}=\frac{v^2}{gr}\\ Where\\v=\frac{2\pi R}{T} \\So\\u_{s}=\frac{(\frac{2\pi R}{T} )^2}{gr} \\u_{s}=\frac{4\pi^2 r}{gT^2}

Substitute the given values

So

u_{s}=\frac{4\pi^2 5.5m}{(9.8m/s^2)(6.3s)^2} \\u_{s}=0.56

6 0
3 years ago
Indicate on the chart whether you would classify each model as representing an element, compound, or mixture.
Ne4ueva [31]

Answer:

1 compound

2 mixture

3 elements

4 0
3 years ago
Read 2 more answers
Show all work.
lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

F=mg (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance r from the centre of the Earth is given by

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

F=\frac{GMm}{r^2}

When the astronaut is on the Earth's surface, r=R (where R is the Earth's radius), so his weight is

F=\frac{GMm}{R^2}=640 N

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

r'=3R+R=4R

Therefore, the new weight is

F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}

Which means that his weight has decreased by a factor 16: therefore, the new weight is

F'=\frac{640}{16}=40 N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0
3 years ago
Problem I Marcella (see warmup problem, above) gets her car moving steadily at 4m/s but suddenly someone stops ahead to assist h
Nady [450]

Answer:

Explanation:

a) KE = (1/2) * m * (v^{2}) = F * d = 14m * 200N = 2800 m/N or 2.8 * 10^{3} m/N

b) 0J and 0m/s (if Marcella stopped after going 14 meters)

c)  Known from part (a) that KE = 2800 J = F1 * d1,

    2800J = F1 * (14m - 1m)  => F1 = 2800J/13m = 215.384 N

   

3 0
3 years ago
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