Sound produced when sections of a string vibrate separately are called
1 answer:
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Answer:
9.8 m/s
Explanation:
The work done by the force pushing the cart is equal to the kinetic energy gained by the cart:
where
W is the work done
is the final kinetic energy of the cart
is the initial kinetic energy of the cart, which is zero because the cart starts from rest, so we can write:
But the work is equal to the product between the pushing force F and the displacement, so
So, the final kinetic energy of the cart is 480 J. The formula for the kinetic energy is
(1)
where m is the mass of the cart and v its final speed.
We can find the mass because we know the weight of the cart, 98.0 N:
Therefore, we can now re-arrange eq.(1) to find the final speed of the cart:
Answer:
the weight of the rider is 493.53 N
Explanation:
Given the data in the question and as illustrated in the image below,
Tension T = 1900 N
the rider is moving at a constant speed so the net force in the horizontal direction will be 0
In the horizontal direction
Fcos( 30° ) = Tcos ( 17° )
F = Tcos( 17° ) / cos( 30° )
F = 1900cos( 17° ) / cos( 30° )
F = 2098.07 N
Now, In the vertical direction,
F sin( 30° ) = W + T sin( 17° )
W = F sin( 30° ) - T sin( 17° )
W = 2098.07sin( 30° ) - 1900sin( 17° )
W = 1049.035 - 555.506
W = 493.53 N
Therefore, the weight of the rider is 493.53 N
