Explanation:
When carbon atom tends to form single bonds then its hybridization is 
, when carbon atom tends to form double bond then its hybridization is 
and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.
For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.
So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.
Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:
Answer:
C. atomic mass
Explanation:
John Dalton was a very versatile man. His work is important in physics, meteorology, medicine (description of color blindness) and chemistry. He was included in researching of partial pressures and atomic theory. He proposed one of the first models of atom in the beginning of 19th century.
He published a table where he proposed relative atomic weight of six atoms. In his honor, standardized unit for atomic weight is called dalton (Da) and weighs 1/12 of carbon atom weight.
Aluminum I think hope this helps
Answer:
7.22 x 10²³molecules
Explanation:
Given parameters:
Number of moles of hydrogen = 1.2moles
Unknown:
Number of molecules of hydrogen = ?
Solution:
From the concept of moles, a mole of a substance contains the Avogadro's number of particles.
1 mole of a substance = 6.02 x 10²³ molecules;
So; 1.2 moles of hydrogen = 1.2 x 6.02 x 10²³ molecules;
= 7.22 x 10²³molecules
The electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3 (option D).
<h3>What is electronic configuration?</h3>
Electronic configuration is the the arrangement of electrons in an atom, molecule, or other physical structure like a crystal.
Vanadium is the 23rd element on the periodic table and has chemical symbol V with atomic number 23. It is a transition metal, used in the production of special steels.
This suggests that the electronic configuration of Vanadium will be written as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3
Therefore, the electronic configuration for vanadium (V) in the periodic table is as follows: 1s2 2s2 2p6 3s2 3p6 4s2 3d3.
Learn more about electronic configuration at: brainly.com/question/14283892
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