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vaieri [72.5K]
3 years ago
15

Divide 98.66 grams by 10.3 mL

Chemistry
1 answer:
ivolga24 [154]3 years ago
8 0

9.58 g·mL⁻¹; 13 mL

In division problems, your answer can have no more significant figures than the number with the fewest significant figures.

98.66 g/10.3 mL = 9.578 640 777g·mL⁻¹ (by my calculator)

There are <em>four</em> significant figures in 98.66, but only <em>three</em> in 10.3.

You must round off your answer to <em>three</em> significant figures.

9.578 640 777 → 9.58 (to three significant figures)

∴ 98.66 g/10.3 mL = 9.58 g·mL⁻¹

______________________________________

When adding values, you must round your answer to the <em>same "place"</em> as the measurement with its <em>last significant figure furthest to the left</em>.  

   4.5   mL

+5.66 mL

+3      mL

13.16 mL

The “3” in “3 mL”has its last significant figure furthest to the left, so you round off the number to the “units" place. That's the last column that the measurements share.

13.16 → 13 (rounded to the “units” place)

∴ 4.5 mL + 5.66 mL + 3 mL = 13 mL

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Answer: Boiling chips provide surfaces on which bubbles can form as the liquid boils.

Hope this helps!
6 0
3 years ago
Limestone stalactites and stalagmites are formed in caves by the following reaction: Ca2 (aq) 2HCO−3(aq)→CaCO3(s) CO2(g) H2O(l)
Vesna [10]

Answer : The value of \Delta E for this reaction is 36.18 kJ

Explanation :

First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.

As per first law of thermodynamic,

\Delta E=q+w

where,

\Delta E = internal energy  of the system

q = heat added or rejected by the system

w = work done

As we are given that:

q = 38.65 kJ

w = -2.47 kJ (system work done on surrounding)

Now put all the given values in the above expression, we get:

\Delta E=38.65kJ+(-2.47kJ)

\Delta E=36.18kJ

Therefore, the value of \Delta E for this reaction is 36.18 kJ

6 0
3 years ago
Consider the generic reaction: 2 A(g) + B(g) → 2 C(g). If a flask initially contains 1.0 atm of A and 1.0 atm of B, what is the
irina1246 [14]

Answer:

b. 1.5 atm.

Explanation:

Hello!

In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:

P=P_A+P_B+P_C

Now, if we introduce the stoichiometry, and the change in the pressure x we can write:

P=1.0-2x+1.0-x+2x

Nevertheless, since the reaction goes to completion, all A is consumed and there is a leftover of B, and that consumed A is:

x=\frac{1.0atm}{2}=0.5atm

Thus, the final pressure is:

P=1.0-2(0.5)+1.0-(0.5)+2(0.5)\\\\P=1.5atm

Therefore the answer is b. 1.5 atm.

Best regards!

3 0
3 years ago
What is the final pressure of a system (atm) that has the volume increased from 0.75 l to 1.1 l with an initial pressure of 1.25
lana66690 [7]
Boyle's law states that pressure is inversely proportional to volume of gas at constant temperature 
PV = k
where P - pressure , V - volume and k - constant 
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting these values in the equation 
1.25 atm x 0.75 L = P x 1.1 L
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3 0
3 years ago
How is alkyne converted to acetone?
cricket20 [7]

Answer:

Propyne can be converted to the acetone when it is made to undergo the reaction with mercuric sulphate followed by hydrolysis and thus, resultant product, thus formed is acetone.

Explanation:

3 0
3 years ago
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