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vovangra [49]
3 years ago
6

Describe the number of signals and their splitting in the 1H NMR spectrum of (CH3)2CHOCH3.

Chemistry
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

d. 3 signals: a singlet, a doublet, and a septet

Explanation:

In this case, we can start with the structure of (CH_3)_2CHOCH_3 . When we draw the molecule we will obtain <u>2-methoxypropane</u> (see figure 1).

In 2-methoxypropane we will have three signals. The signal for the CH_3  groups in the left, the CH  and the CH_3  in the right. Lets analyse each one:

-) CH_3  in the right

In this carbon, we dont have any hydrogen as neighbors. Therfore we will have <u>singlet</u> signal in this carbon.

-) CH

In this case, we have 6 hydrogen neighbors ( the two methyl groups in the left). So, if we follow the <u>n + 1 rule</u> (where n is the amount of hydrogen neighbors):

multiplicity~=~n+1~=~6~+~1~=~7

For this carbon we will have a <u>septet</u>.

-) CH_3  in the left

In this case we have only 1 hydrogen neighbor (the hydrogen in CH ). So, if we use the n+1 rule we will have:

multiplicity~=~n+1~=~1~+~1~=~2

We will have a doublet

With all this in mind the answer would be:  

<u>d. 3 signals: a singlet, a doublet, and a septet </u>

<u />

See figure 2 to further explanations

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