2.40 kJ of heat is added to a slug of platinum and a separate 2.40 kJ of heat is added to a slug of zinc. The heat capacity of t
he platinum slug is 209J/°C while the heat capacity of the zinc slug is 575 J/°C. If the slugs are each originally at 25.00°C, what is the final temperature of each slug?
1 answer:
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Answer:
rate = k[A][B] where k = k₂K
Explanation:
Your mechanism is a slow step with a prior equilibrium:
(The arrow in Step 1 should be equilibrium arrows).
1. Write the rate equations:
2. Derive the rate law
Assume k₋₁ ≫ k₂.
Then, in effect, we have an equilibrium that is only slightly disturbed by C slowly reacting to form D.
In an equilibrium, the forward and reverse rates are equal:
k₁[A][B] = k₋₁[C]
[C] = (k₁/k₋₁)[A][B] = K[A][B] (K is the equilibrium constant)
rate = d[D]/dt = k₂[C] = k₂K[A][B] = k[A][B]
The rate law is
rate = k[A][B] where k = k₂K
Answer:
(a)
(b)
(c)
Explanation:
Hello,
(a) In this case, since entropy remains unchanged, the constant should be computed for air as an ideal gas by:
Next, we compute the final temperature:
Thus, the work is computed by:
(b) In this case, since is given, we compute the final temperature as well:
And the isentropic work:
(c) Finally, for isothermal, final temperature is not required as it could be computed as:
Regards.