Answer:
F = 8 N
Explanation:
Given,
The mass of the smaller block, m = 20 Kg
The mass of the larger block, M = 96 Kg
The coefficient of the static friction, μ = 0.4
The static friction force acting on a body is the minimum horizontal force that is required to keep the smaller block from slipping down the larger block. It is given by the formula,
F = μ · η N
Where, η - normal force acting on the body
F = 0.5 x 20
= 8 N
Hence, the minimum horizontal force that is required to keep the smaller block from slipping down the larger block is, F = 8 N.
Answer:
Increasing speed.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
![Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}](https://tex.z-dn.net/?f=Acceleration%20%28a%29%20%3D%20%5Cfrac%7Bfinal%20%5C%3B%20velocity%20%20-%20%20initial%20%5C%3B%20velocity%7D%7Btime%7D)
In this scenario, an object moves with a positive acceleration. Thus, the object is moving with an increasing speed and as such it has acceleration in the same direction as its velocity with respect to time.
Lake water flows downward through tunnels
- water's gravity PE to water's KE
Flowing water turns turbines
- water's KE to turbines' KE
Turbines generate electricity
turbines' KE to electrical energy.
Answer:
yes that is true because if you put the solar thing in the sunlight it gets converted to electricity
Answer:
95.38 %
Explanation:
Transformer is an electrical device which has two or more coils of wire used to transfer electrical energy by changing magnetic field
Power of a transformer coil = voltage * Current
Transformer does not require any moving parts to transfer energy. Therefore we cannot see any friction or windage losses here. But they have some types of losses called “copper losses” and “iron losses” but generally these are quite small.
So there for it can affect the efficiency of the transformer also. Efficiency can be defined as follow
![efficiency=\frac{P_(out)}{P_(in)}*100 \\=\frac{V_(secondary)*I_(secondary)}{V_(primary)*V_(primary)} *100\\=\frac{19.4*11.8}{120*2} *100\\=95.38 %](https://tex.z-dn.net/?f=efficiency%3D%5Cfrac%7BP_%28out%29%7D%7BP_%28in%29%7D%2A100%20%5C%5C%3D%5Cfrac%7BV_%28secondary%29%2AI_%28secondary%29%7D%7BV_%28primary%29%2AV_%28primary%29%7D%20%2A100%5C%5C%3D%5Cfrac%7B19.4%2A11.8%7D%7B120%2A2%7D%20%2A100%5C%5C%3D95.38%20%25)