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mart [117]
3 years ago
9

Which of the following states Bernoulli’s principle?

Physics
1 answer:
madam [21]3 years ago
8 0
The correct answer is <span>B. As speed of a fluid increases, the pressure within decreases.
Using formulas, Bernoulli's principle can be written as 
</span>p+ \frac{1}{2}\rho v^2 + \rho g h=cost.
where p is the pressure of the fluid, \rho its density, v its speed, and h its elevation above a reference level.
Assuming h does not change, we can see that if the speed v increases, the pressure p must decrease in order  to keep constant the sum of the three terms.
You might be interested in
Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
USPshnik [31]

Explanation:

S=(V^2-U^2)/2a a=g (gravity) a=10

=(0^2-25^2/2*(-10)

=625/20

=31.25m

6 0
2 years ago
A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
Consider the path of a comet orbiting a star, the system of the comet plus the star. Which of the following statements are corre
Stels [109]

Answer:

True  1, 4

False 2, 3, 5

Explanation:

The system is formed by the Sun that is fixed at a point (focus of movement) and the comet that rotates around in styptic orbits. The only force involved is the force of attraction between the two bodies, if we write the energy of the system

         Em = K + U

         Em = ½ m v2 + G m Ms / r2

where m is the mass of the comet, Ms the mass of the Sun and r the distance between them.

This system is isolated so the energy is conserved throughout the movement, it only transforms from kinetic to gravitational potential.

Let's review the different claims;

1) True. The speed of the comet determines its kinetic energy, so when decreasing the speed decreases the kinetic energy, there is also a decrease due to the lost mass

2) False. The total energy is constant, so if the kinetic energy increases, the power energy must decrease

3) False. The comet's speed changes are due to changes in gravitational energy, so no external work is needed to change the speed.

4) True. Correct because the sum of the two must be constant

5) False. When the comet loses speed, the energy increases, the power would gravitate, so there is no loss of energy, we are ignoring the loss of mass of the comet.

8 0
3 years ago
Capacitors C1 = 5.85 µF and C2 = 2.80 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon
posledela

Answer:

Q1_new = 515.68 µC

Q2_new = 246.82 µC

Explanation:

Since the capacitors are charged in parallel and not in series, then both are at 250 V when they are disconnected from the battery.

Then it is only necessary to calculate the charge on each capacitor:

Q1 = 5.85 µF * 250 V = 1462.5 µC

Q2 = 2.8 µF * 250 V = 700 µC

Now, we will look at 1462.5 µC as excess negative charges on one plate, and 1462.5 µC as excess positive charges on the other plate. Now, we will use this same logic for the smaller capacitor.

When there is a connection of positive plate of C1 to the negative plate of C2, and also a connection of the negative plate of C1 to the positive plate of C2, some of these excess opposite charges will combine and cancel each other. The result is that of a net charge:

1462.5 µC - 700 µC = 762.5 µC

Thus,762.5 µC of net charge will remain in the 'new' positive and negative plates of the resulting capacitor system.

This 762.5 µC will be divided proportionately between the two capacitors.

Q1_new = 762.5 µC * (5.85/(5.85 + 2.8)) = 515.68 µC

Q2_new = 762.5 µC * (2.8/(5.85 + 2.8) = 246.82 µC

4 0
4 years ago
A car speeds up from 13 m/s to 23 m/s in 30 seconds. What is the acceleration of the car?
ra1l [238]
Well, <span>v = u + a×t is the equation.</span>
<span>
v: final velocity, which is 23 m/s in this equation.</span>
<span>u: initialo velocity = 13 m/s </span>
<span>a: acceleration = ? </span>
<span>t: time = 30s 
</span>
Your equation would be...

<span>23 = 13 + a×30 </span>
<span>a = (23 - 13) / 30 </span>
<span>a = 1 / 3 </span>
<span>a = 0.333 m/s</span>
7 0
3 years ago
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