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3 years ago

a 2 kilogram wooden block raised on an inclined plane making angle 30 degree frictional force will be equal to

Physics

1 answer:

nata0808 [166]3 years ago

8 0

Answer:

fvSvfbikufdclknfmfl us

Explanation:

cuz

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How fast do you need to swing a 250-g ball at the end of a string in a horizontal circle of 0.6-m radius so that the string make

serious [3.7K]

Answer:

2.7 m/s

Explanation:

Draw a free body diagram of the ball. There are two forces:

Weight force mg pulling down

Tension force T pulling 39° above the horizontal

Sum of the forces in the y direction:

∑F = ma

T sin θ − mg = 0

T = mg / sin θ

Sum of the forces in the radial (+x) direction:

∑F = ma

T cos θ = m v² / r

Substitute:

(mg / sin θ) cos θ = m v² / r

mg / tan θ = m v² / r

g / tan θ = v² / r

v = √(gr / tan θ)

Given that r = 0.6 m and θ = 39°:

v = √(9.8 m/s² × 0.6 m / tan 39°)

v ≈ 2.7 m/s

8 0

3 years ago

The main difference between speed and velocity involves

grigory [225]

The main difference is direction. C.

Speed is a scalar quantity, while Velocity is a vector quantity.
Speed is measured without taking into fact direction, but Velocity takes into fact the direction.

3 0

3 years ago

Potassium chlorate decomposes to produce 20 g of solid potassium chloride. Oxygen gas is also produced. Which best describes the

jok3333 [9.3K]

Hi lovely,

The answer you're looking for would be B.

6 0

3 years ago

The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current

Komok [63]

Answer:

$I=0.047A$

Explanation:

Let's use Ohm's law:

$V=IR$

$I=\frac{V}{R}$ (1)

Where:

$V=Voltage\\I=Current\\R=Electrical\hspace{2 mm}Resistance$

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:

$R=\rho*\frac{l}{A}$ (2)

Where:

$R=Electrical\hspace{2 mm}Resistance\\l=Length\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=80m\\A=Cross\hspace{2 mm}sectional\hspace{2 mm}area\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=1.256637061*10^{-7} \\\rho=Electrical\hspace{2 mm}resistivity\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}material=2.35*10^{-8}$

Keep in mind that the electrical resistivity of the gold is a known constant which is $\rho_g_o_l_d=2.35*10^{-8}$ and the cross sectional area of the conductor is calculated as: