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Sergio [31]
3 years ago
9

Is KBr a covalent or ionic compound

Physics
2 answers:
raketka [301]3 years ago
6 0

Answer:

Ionic Compound

Explanation:

To identify the type of chemical bond in a molecule, look at the atoms that make up the compound. If there are two nonmetals, it is a covalent bond. If the two atoms are metals, it is a metallic bond. If one atom is a metal and the other is a nonmetal, it is an ionic bond. Ionic compounds are also known as salts. You can identify KBr as an ionic compound because potassium is a metal and a salt.

Hope this helps

motikmotik3 years ago
5 0

Ionic Compound

KBr ( Pottasium Bromide ) .

Ionic compounds are also known as salts.

  • KBr as an ionic compound because Pottasium is a metal and Bromine is a non metal .

  • KBr is an ionic compound due to the type of bonding that occurs between the two elements - an electrostatic attraction between the two ions.

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If a point has 40 J of energy and the electric potential is 8 V, what must be the charge?
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If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C

<u>Given the following the details;</u>

  • Energy = 40 Joules
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To find the quantity of charge;

Mathematically, the quantity of charge with respect to electric potential is given by the formula;

Quantity \; of \; charge = \frac{Energy}{Electric \; potential}

Substituting the values into the formula, we have;

Quantity \; of \; charge = \frac{40}{8}

<em>Quantity of charge = 5 Coulombs</em>

Therefore, the quantity of charge must be <em>5 Coulombs.</em>

Find more information: brainly.com/question/21808222

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Answer:

Cannonball b spends more time in the air than cannonball a.

Explanation:

Starting with the definition of acceleration, we have that:

a=\frac{\Delta v}{\Delta t}\\\\\Delta t= \frac{\Delta v}{a}

Since both cannonballs will stop in their maximum height, their final velocity is zero. And since the acceleration in the y-axis is g, we have:

\Delta t= -\frac{v_{oy}}{g}

Now, this time interval is from the moment the cannonballs are launched to the moment of their maximum height, exactly the half of their time in the air. So their flying time t_f is (the minus sign is ignored since we are interested in the magnitudes only):

t_f=2\frac{v_{oy}}{g}

Then, we can see that the time the cannonballs spend in the air is proportional to the vertical component of the initial velocity. And we know that:

v_{oy}=v_o\sin\theta\\\\\implies t_f=2\frac{v_o\sin\theta}{g}

Finally, since \sin60\°=\frac{\sqrt{3} }{2} and \sin45\°=\frac{\sqrt{2} }{2}, we can conclude that:

t_{fa}=\sqrt{2}\frac{v_o }{g} \\\\t_{fb}=\sqrt{3}\frac{v_o }{g}\\\\\implies t_{fb}>t_{fa}

In words, the cannonball b spends more time in the air than cannonball a.

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3 years ago
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Explanation:

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zubka84 [21]

Answer:

The Bohr model shows that the electrons in atoms are in orbits of differing energy around the nucleus

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