Answer:
Explanation:
Given data
Speed of jet Vjet=1190 km/h
Speed of prop driven Vprop=595 km/h
Height of jet 7.5 km
Height of prop driven transport 3.8 km
Density of Air at height 10 km p7.8=0.53 kg/m³
Density of air at height 3.8 km p3.8=0.74 kg/m³
The drag force is given by:
The ratio between the drag force on the jet to the drag force on prop-driven transport is then given by:
Answer:
12
N
in the direction opposite to electric field.
Explanation:
Force on a charged particle
q
due to electric field
E
is given by
→
F
=
q
→
E
|
F
|
=
−
0.06
C
×
200
N
C
=
−
12 N
Here negative indicates that force is in the direction opposite to electric field.
Answer:
(a) the runner's kinetic energy at the given instant is 308 J
(b) the kinetic energy increased by a factor of 4.
Explanation:
Given;
mass of the runner, m = 64.1 kg
speed of the runner, u = 3.10 m/s
(a) the kinetic energy of the runner at this instant is calculated as;
(b) when the runner doubles his speed, his final kinetic energy is calculated as;
the change in the kinetic energy is calculated as;
Thus, the kinetic energy increased by a factor of 4.
Answer:12.28m/s
Explanation:
momentum of baseball =mass of baseball x velocity of baseball
Momentum of baseball =0.31x21
Momentum of baseball =6.51kgm/s
For a softball to have same momentum with the baseball we can say :momentum of baseball =mass of softball x velocity of softball
6.51=0.53 x velocity of softball
Velocity of softball =6.51/0.53
Velocity of softball =12.28m/s
Responder:
E = 1440 kJ
Explicación:
Se da que,
La potencia de un horno de cocción es de 800 W
El voltaje al que se opera es de 230 V
Tiempo, t = 30 minutos = 1800 segundos
Necesitamos encontrar la energía eléctrica utilizada por el horno de cocción. El producto de la potencia y el tiempo es igual a la energía consumida. Entonces,
