It was named the Qumran seas scrolls.
<h3>Answer:</h3>
[OH⁻] = 1.0 × 10⁻¹⁰ M
<h3>Solution:</h3>
In order to calculate concentration of hydroxide ion i.e. [OH⁻] first we will find the pOH by using following relation,
pH + pOH = 14
Putting value of pH given and solving for pOH,
4.0 + pOH = 14
pOH = 14 - 4.0
pOH = 10.0
As ,
pOH = -log [OH⁻]
So,
[OH⁻] = 10^-pOH
Putting value of pOH,
[OH⁻] = 10⁻¹⁰
[OH⁻] = 1.0 × 10⁻¹⁰ M
"In 1897, J.J. Thomson discovered the electron by experimenting with a Crookes, or cathode ray, tube. He demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas."
Source:abcte.org