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GREYUIT [131]
3 years ago
10

What caused the bonding of two atoms which undergo an ionic bond?

Chemistry
1 answer:
Keith_Richards [23]3 years ago
8 0
C. As we know, an atom is made of three parts--protons (+), neutrons (core), and electrons (-) When one of these atoms loses one or more electron(s), it becomes a cation, or a positively charged ion. Inversely, when this atom gains a positively charged ion, [the atom] becomes a negatively charged atom, or an anion. The bond is made through electrostatic attraction, and a bond between these two "halves of a whole", it is known as an ionic bond.
annoyedfish1542
2 years ago
what
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Describe what happens in a condensation reactions
dlinn [17]
A condensation reaction is described to be a reaction wherein two molecules form an even larger product and consequently produces a smaller molecule as a by-product. For example, when two amino acids are combined, a dipeptide bond is formed. As a result, 1 molecule of water is produced as a by-product.
5 0
3 years ago
Which scenario suggests that the results of an experiment are reliable?
BigorU [14]
The answer is B.

Hope this helps.
4 0
3 years ago
Read 2 more answers
A sample of ammonia gas at 75°c and 445 mm hg has a volume of 16.0 l. what volume will it occupy if the pressure rises to 1225 m
ioda
In this kind of exercises, you should  use the "ideal gas" rules: PV = nRT
P should be in Pascal: 
445mmHg = 59328Pa
1225mmHg = 163319Pa

V should be in cubic meter:
16L = 0.016 m3

R = \frac{PV}{nT} = constant
\frac{P1 V1}{n T} = \frac{P2 V2}{n T}
==> P1 * V1 = P2 * V2
V2 = \frac{P1 V1}{P2} = \frac{445 0.016}{1225}
V2 = 0.00581 m3 = 5.81 L


7 0
4 years ago
Amphetamine (C9H13N)(C9H13N) is a weak base with a pKbpKb of 4.2. You may want to reference (Pages 710 - 713) Section 16.8 while
Soloha48 [4]

Answer:

pH = 10.38

Explanation:

  • C9H13N ↔ C9H20O3N+  +  OH-

∴ molar mass C9H13N = 135.21 g/mol

∴ pKb = - log Kb = 4.2

⇒ Kb = 6.309 E-5 = [OH-][C9H20O3N+] / [C9H13N]

∴ <em>C</em> sln = (205 mg/L )*(g/1000 mg)*(mol/135.21 g) = 1.516 E-3 M

mass balance:

⇒ <em>C</em> sln = 1.516 E-3 = [C9H20O3N+] + [C9H13N]......(1)

charge balance:

⇒ [C9H20O3N+] + [H3O+] = [OH-]; [H3O+] is neglected, come from water

⇒ [C9H20O3N+] = [OH-].......(2)

(2) in (1):

⇒ [C9H13N] = 1.516 E-3 - [OH-]

replacing in Kb:

⇒ Kb = 6.3096 E-5 = [OH-]² / (1.516 E-3 - [OH-])

⇒ [OH-]² + 6.3096 E-5[OH] - 7.26613 E-8 = 0

⇒ [OH-] = 2.3985 E-4 M

∴ pOH = - Log [OH-]

⇒ pOH = 3.62

⇒ pH = 14 - pOH = 14 - 3.62 = 10.38

5 0
3 years ago
Use the portion of the periodic table shown below to answer the questions
leva [86]

Answer:

Part 1:sodium

rubidium

Part 2: protons neutrons and electrons are all 12

The number of protons is equal to the no. of neutrons from the electronic arrangement of magnesium and the no. of electrons is got from the atomic no. of magnesium

8 0
3 years ago
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