Calculate the pH of 0.005 methonoic acid solution given that the degree of dissociation is 0.057
1 answer:
Answer:
pH = 2.77
Explanation:
Data Given:
degree of dissociation Ka = 0.057
Concentration of Methanoic acid = 0.005 M
pH = ?
Solution:
First we calculate Hydrogen ion concentration
Formula will be used
[H⁺] = . . . . . . (1)
where
Ka = degree of dissociation
c = concentration
Put values in formula 1
[H⁺] = . . . . . . (1)
[H⁺] = 0.0017 M
Now Calculate the pH
As we know
pH = -log [H⁺] . . . . . .(2)
Put values in equation
pH = - log [ 0.0017 M]
pH = - [-2.77]
pH = 2.77
So,
pH of methanoic acid = 2.77
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Single displacement reaction : It is a type of chemical reaction in which the more reactive element displaces the less reactive element.
Option A reaction :
It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.
Option B reaction :
It is an example of single displacement reaction.
Option C reaction :
It is an example of combination reaction because in this reaction two reactants react to give a single product.
Option D reaction :
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Option E reaction :
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Hence, the options B and E are single displacement reactions.