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3 years ago

PLEASE ANSWER!!!

Chemistry

1 answer:

Alexus [3.1K]3 years ago

8 0

Answer:

In the case of water, an object with a density less than 1 g/cm3 will float. The closer its density is to 1 g/cm3, the more of it will sit below the water level.

Explanation:

Whether an object will float or sink is dependent on its density, and on the density of the liquid it is placed in.

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Give all possible ml values for orbitals that have each of the following: (a) l = 3;

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At l = 3, ml =+3,+2,+1,0,-1,-2,-3

What are quantum numbers?

Quantum numbers are used to describe where around a nucleus a particular electron can be found.
In any given atom, each electron can be described by four quantum numbers.
These are n,l,m1,ms
The values that each number can be are based on a set of rules.

What is a magnetic quantum number ?

It describes the orientation of the orbitals.
It is represented as ml.
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Answer:

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A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in

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Answer:

The molarity of the strong base is 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

Explanation:

Step 1: Data given

Molarity of H2SO4 = 0.250 M

The initial buret reading is 5.00 mL

The final reading is 30.00 mL

Step 2: Calculate volume of H2SO4 used

30.00 mL - 5.00 mL = 25.00 mL

Step 3: Calculate moles of H2SO4

0.250 M = 0.250 mol/L

Since there are 2 H+ ions per H2SO4

0.250 mol/L * 2 = 0.500 mol/L

The number of moles H2SO4 = 0.500 mol/L * 0.025 L

Number of moles H2SO4 = 0.0125 mol

Step 4: Calculate moles of OH-

For 1 mol H2SO4, we need 1 mol of OH-

For 0.0125 mol of H2SO4, we have 0.0125 mol of OH-

Step 5: Calculate the molarity of the strong base

Molarity = moles / volume

Molarity OH- = 0.0125 mol / 0.02 L

Molarity OH - = 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

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