Calculate a sm for the equation below. (Round to the nearest whole number.) 4NH, (g) +50, (g) → 4NO(g) + 6H2O(g) = 192.8 J/mol K
2 answers:
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According to law of definite proportion:
In a compound, elements are always arranged in fixed ratio by mass.
Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.
Converting mass into number of moles:
Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,
Similarly, number of moles of oxygen will be:
The ratio of number of moles of carbon and oxygen will be:
Therefore, formula of compound will be CO.
Sample 2:
It has 36.22 g Carbon and 48.00 g Oxygen.
Converting mass into number of moles:
Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,
Similarly, number of moles of oxygen will be:
The ratio of number of moles of carbon and oxygen will be:
The formula of compound will be CO.
Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.
The arrangement of molecules within the 3 phases of matter are shown in the picture.
For the solid, the molecules are packed closely together. They don't have much space to move, so they just practically vibrate. For the liquid, the molecules are relatively farther from each other. The liquid molecules can flow freely but not as much as the gases. In the gases, the molecules are very far from each other. They are very sensitive to slight changes of pressure, volume and temperature.
For the solid, the molecules are packed closely together. They don't have much space to move, so they just practically vibrate. For the liquid, the molecules are relatively farther from each other. The liquid molecules can flow freely but not as much as the gases. In the gases, the molecules are very far from each other. They are very sensitive to slight changes of pressure, volume and temperature.