Answer:
2,000
Step-by-step explanation:
write out an equation that represents the problem. the original price X fell by 15% to a new price of 1700:
X - (X*15%) = 1700
X(1-0.15) =1700
X=1700/(1-0.15)
X=2,000
convert 15% to decimal form:
15%=0.15
Answer:
2
Step-by-step explanation:
So I'm going to use vieta's formula.
Let u and v the zeros of the given quadratic in ax^2+bx+c form.
By vieta's formula:
1) u+v=-b/a
2) uv=c/a
We are also given not by the formula but by this problem:
3) u+v=uv
If we plug 1) and 2) into 3) we get:
-b/a=c/a
Multiply both sides by a:
-b=c
Here we have:
a=3
b=-(3k-2)
c=-(k-6)
So we are solving
-b=c for k:
3k-2=-(k-6)
Distribute:
3k-2=-k+6
Add k on both sides:
4k-2=6
Add 2 on both side:
4k=8
Divide both sides by 4:
k=2
Let's check:
:
![3x^2-(3\cdot 2-2)x-(2-6)](https://tex.z-dn.net/?f=3x%5E2-%283%5Ccdot%202-2%29x-%282-6%29)
![3x^2-4x+4](https://tex.z-dn.net/?f=3x%5E2-4x%2B4)
I'm going to solve
for x using the quadratic formula:
![\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpm%20%5Csqrt%7B%28-4%29%5E2-4%283%29%284%29%7D%7D%7B2%283%29%7D)
![\frac{4\pm \sqrt{16-16(3)}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpm%20%5Csqrt%7B16-16%283%29%7D%7D%7B6%7D)
![\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpm%20%5Csqrt%7B16%7D%5Csqrt%7B1-%283%29%7D%7D%7B6%7D)
![\frac{4\pm 4\sqrt{-2}}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B4%5Cpm%204%5Csqrt%7B-2%7D%7D%7B6%7D)
![\frac{2\pm 2\sqrt{-2}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpm%202%5Csqrt%7B-2%7D%7D%7B3%7D)
![\frac{2\pm 2i\sqrt{2}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpm%202i%5Csqrt%7B2%7D%7D%7B3%7D)
Let's see if uv=u+v holds.
![uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}](https://tex.z-dn.net/?f=uv%3D%5Cfrac%7B2%2B2i%5Csqrt%7B2%7D%7D%7B3%7D%20%5Ccdot%20%5Cfrac%7B2-2i%5Csqrt%7B2%7D%7D%7B3%7D)
Keep in mind you are multiplying conjugates:
![uv=\frac{1}{9}(4-4i^2(2))](https://tex.z-dn.net/?f=uv%3D%5Cfrac%7B1%7D%7B9%7D%284-4i%5E2%282%29%29)
![uv=\frac{1}{9}(4+4(2))](https://tex.z-dn.net/?f=uv%3D%5Cfrac%7B1%7D%7B9%7D%284%2B4%282%29%29)
![uv=\frac{12}{9}=\frac{4}{3}](https://tex.z-dn.net/?f=uv%3D%5Cfrac%7B12%7D%7B9%7D%3D%5Cfrac%7B4%7D%7B3%7D)
Let's see what u+v is now:
![u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}](https://tex.z-dn.net/?f=u%2Bv%3D%5Cfrac%7B2%2B2i%5Csqrt%7B2%7D%7D%7B3%7D%2B%5Cfrac%7B2-2i%5Csqrt%7B2%7D%7D%7B3%7D)
![u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}](https://tex.z-dn.net/?f=u%2Bv%3D%5Cfrac%7B2%7D%7B3%7D%2B%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7B4%7D%7B3%7D)
We have confirmed uv=u+v for k=2.
Answer:
x = 14
Step-by-step explanation:
Since they are similar triangles, their sides are proportional
12 : 15 :: 8 : x - 4
Product of extremes = Product of means
12 × ( x- 4 ) = 15 × 8
12x -48 = 120
12x = 120 + 48
12x = 168
x = 168/12
x = 14
Answer:
<em>P=760</em>
Step-by-step explanation:
Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.
Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).
This shape has sides that are parallel to both axes.
To calculate the perimeter we find the length of two sides.
The distance from A to B is the difference between their y-axis:
w=112-(-3)=115
The distance from A to C is the difference between their x-axis:
l=2-(-212)=215
It's evident this is not a square but a rectangle. The perimeter is
P=2w+2l=330+430
P=760
Answer:
the new ones and the old ones that you didn’t delete
Step-by-step explanation: