The diagonal of the tv screen is given by:
d = root ((w) ^ 2 + (h) ^ 2)
Where,
w: width
h: height
In addition we have the following relationship:
h / w = 8/15
Thus,
For the width:
d = root ((w) ^ 2 + ((8/15) w) ^ 2)
For the high:
d = root (((15/8) h) ^ 2 + (h) ^ 2)
Answer:
The expressions for the width and height of a wide-screen tv in terms of the length of its diagonal are:
d = root ((w) ^ 2 + ((8/15) w) ^ 2)
d = root (((15/8) h) ^ 2 + (h) ^ 2)
67 with the remainder of 31 I hope this helps lol
-z³ + 5k^6 + z³ -10k^6
(-z³ cancels out with z³)
5k^6 -10k^6
(then subtract)
Answer is -5k^6
Answer:
r³ + 15r² - 10r - 4
Step-by-step explanation:
First, note you can remove the brackets, in this case they contribute nothing at all.
Then, group the like terms and add them, e.g., we have 3r³ and -2r², they add up to r³.
Finally, order them from greatest power of r to smallest power of r.
That's all!
