Answer:
The automobile tire rotates 91 revolutions
Explanation:
Given;
angular acceleration of the automobile, α = 2.13 rad/s²
time interval, t = 23.2-s
To calculate the number of revolutions, we apply the first kinematic equation;
the initial angular velocity is zero,
Find how many revolutions that are in 573.2256 Rad
Therefore, the automobile tire rotates 91 revolutions
Because there is no record of all things. As we have partially unknow information, it can never be held as a fact.
Explanation:
Given:
v₀ₓ = 15 m/s cos 20° = 14.10 m/s
aₓ = 0 m/s²
v₀ᵧ = 15 m/s sin 20° = 5.13 m/s
aᵧ = -9.8 m/s²
t = 1.5 s
Find: Δx and Δy
Δx = v₀ₓ t + ½ aₓ t²
Δx = (14.10 m/s) (1.5 s) + ½ (0 m/s²) (1.5 s)²
Δx = 21.1 m
Δy = v₀ᵧ t + ½ aᵧ t²
Δy = (5.13 m/s) (1.5 s) + ½ (-9.8 m/s²) (1.5 s)²
Δy = -3.33 m
Explanation:
C,
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Answer:
b. 3 m
Explanation:
The computation of the distance travelled is shown below:
As we know that
Work done = Horizontal Force × distance travelled
360 J = 120 N × discount travelled
So, the distance travelled is
= 360 J ÷ 120 N
= 3 m
hence, the correct option is b. 3 m
