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gogolik [260]
3 years ago
12

A net force of 60 N north acts on an object with a mass of 30 kg. Use Newton's second law of motion to calculate the amount of a

cceleration the object will experience. Then explain how the amount of acceleration will change if the net force or the mass of the object increases.
Physics
1 answer:
choli [55]3 years ago
4 0
<h3 /><h3>Answers :</h3><h3 />

F = m×a

60 N = 30 kg × a

30 × a = 60

a =  60/30

a =  2 m/s²

<h3 /><h3 />

<em>The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. </em>

<em></em>

Explanation:

If the net force increases while the mass of the object remains the same, the amount of acceleration also increases.

However, when the mass of the object increases while the net force remains the same, the amount of acceleration decreases.  

<h3 />

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rosijanka [135]

Answer:

a= -0.86 m/s²

The negative sign shows that ball down the ground or moving down

Explanation:

Vf² - Vo² = 2gS

where

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g = acceleration due to gravity = 9.8 m/sec^2 (constant)

S = distance travelled by clay = 15 m

Substituting appropriate values,

Vf² - 0 = 2(9.8)(15)  

Vf = 17.15 m/sec.

Formula to use is,  

V - Vf = aT

where

V = velocity of clay when it stops = 0

Vf = 17.15 m/sec (as determined above)

a = acceleration

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Put the values to find acceleration

a=(V-Vf)/T

a=(0-17.15)/20

a= -0.86 m/s²

The negative sign shows that ball down the ground

3 0
3 years ago
Consider the plot below describing motion along a straight line with an initial position of 10 m. −4 −3 −2 −1 0 1 2 3 4 5 6 1 2
Ugo [173]

Answer:

+1 m/s^2

Explanation:

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3 years ago
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dybincka [34]

Answer:

a. b- x= y

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Explanation:

a. x components:

dE = \frac{kdq}{(a+r-x^{2}) } \\

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Integrating and solving gives:

b- x= y

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b. the force is given by the equation derived from (a.):

F = \frac{-kQqi}{r (a+r)}

c. Given that r>>a, the expression becomes:

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Explanation:

When the size of the charge distribution is less than the distance to the deviation point of the charge then the charge distribution would produce the same effect such as a linear charge.

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The valve in the exit pipe is closed . The density of water is 1000kg / m and the gravitational force on free fall of water is 1
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7 0
2 years ago
Read 2 more answers
n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Us
barxatty [35]

Answer:

The answer is "(1.265 \pm 0.010) \ s \ and \ 0.709 \%"

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T_{theo}= 2\pi \sqrt{\frac{l}{g}}

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If  error in the theoretical time period :

\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2}  \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}

           = 0.010 \ s

 T_{theo} = (1.265 \pm 0.010) \ s

In point ii:

\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100

<h3>                     = \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%</h3>
5 0
3 years ago
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