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MA_775_DIABLO [31]
2 years ago
9

Newton's 1st law of motion States that

Physics
1 answer:
ivann1987 [24]2 years ago
7 0

Answer:

B is right at first I thought I was wrong

Explanation:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

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A baseball bat balances 74.9 cm from one end. If an 0.560-kg glove is attached to that end, the balance point moves 25.3 cm towa
timurjin [86]

Answer:

The mass of the bat is 1.09 kg.

Explanation:

Given that,

The balance point of the glove, x = 74.9 cm

Mass of the glove, m = 0.56 kg

Center of mass of the baseball bat, C = 25.3 cm

Let M is the mass of the bat. The center of mass is given by the formula as :

C=\dfrac{MX+mx}{M+m}

X is 0 as it is at a end

C=\dfrac{mx}{M+m}

25.3=\dfrac{0.56\times 74.9}{M+0.56}

M = 1.09 kg

So, the mass of the bat is 1.09 kg. Hence, this is the required solution.

3 0
3 years ago
Running at 1.55 m/s, Bruce, the 40.0 kg quarterback, collides with Biff, the 90.0 kg tackle, who is traveling at 7.0 m/s in the
Margarita [4]

Answer:Bruce is knocked backwards at  

14

m

s

.

Explanation:

This is a problem of momentum (

→

p

) conservation, where

→

p

=

m

→

v

and because momentum is always conserved, in a collision:

→

p

f

=

→

p

i

We are given that  

m

1

=

45

k

g

,  

v

1

=

2

m

s

,  

m

2

=

90

k

g

, and  

v

2

=

7

m

s

The momentum of Bruce (

m

1

) before the collision is given by

→

p

1

=

m

1

v

1

→

p

1

=

(

45

k

g

)

(

2

m

s

)

→

p

1

=

90

k

g

m

s

Similarly, the momentum of Biff (

m

2

) before the collision is given by

→

p

2

=

(

90

k

g

)

(

7

m

s

)

=

630

k

g

m

s

The total linear momentum before the collision is the sum of the momentums of each of the football players.

→

P

=

→

p

t

o

t

=

∑

→

p

→

P

i

=

→

p

1

+

→

p

2

→

P

i

=

90

k

g

m

s

+

630

k

g

m

s

=

720

k

g

m

s

Because momentum is conserved, we know that given a momentum of  

720

k

g

m

s

before the collision, the momentum after the collision will also be  

720

k

g

m

s

. We are given the final velocity of Biff (

v

2

=

1

m

s

) and asked to find the final velocity of Bruce.

→

P

f

=

→

p

1

f

+

→

p

2

f

→

P

f

=

m

1

v

1

f

+

m

2

v

2

f

Solve for  

v

1

:

v

1

f

=

→

P

f

−

m

2

v

2

f

m

1

Using our known values:

v

1

f

=

720

k

g

m

s

−

(

90

k

g

)

(

1

m

s

)

45

k

g

v

1

f

=

14

m

s

∴

Bruce is knocked backwards at  

14

m

s

.

Explanation:

5 0
2 years ago
Are ultrasound waves high energy waves or low energy waves?
german
And think they are high energy waves. But I'm not sure
3 0
3 years ago
3. A wye-connected load has a voltage of 480 V applied to it. What is the voltage dropped across each phase?
ZanzabumX [31]

Answer:

E_s = 277.13V

Explanation:

Given

Load\ Voltage = 480V

Required

Determine the voltage dropped in each stage.

The relation between the load voltage and the voltage dropped in each stage is

E_l = E_s * \sqrt3

Where

E_l  = 480

So, we have:

480 = E_s * \sqrt3

Solve for E_s

E_s = \frac{480}{\sqrt3}

E_s = \frac{480}{1.73205080757}

E_s = 277.128129211

E_s = 277.13V

<em>Hence;</em>

<em>The voltage dropped at each phase is approximately 277.13V</em>

5 0
3 years ago
Name and briefly describe the two types of interference
Annette [7]

The two types of wave interference are constructive and destructive.

These both describe what happens when waves combine

<u>Constructive interference</u> is when 2 waves combine to form a wave with a larger amplitude, but this is only if both waves are both positive or both negative.

<u>Destructive interference</u> is when the two waves are opposite, one is negative, one is positive. They subtract forming the combined wave that has a lower amplitude.

I hope that helps u out!! :)


6 0
3 years ago
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