Answer:
The image distance from right lens is 2.86 cm and image is real.
Explanation:
Given that,
Focal length of left lens = 10 cm
Focal length of right lens = 5 cm
Distance between the lenses d= 15 cm
Object distance = 50 cm
We need to calculate the image distance from left lens
Using formula of lens

Put the value into the formula



We need to calculate the image distance from right lens
The object distance will be

Using formula of lens

Put the value into the formula



The image is real.
Hence, The image distance from right lens is 2.86 cm and image is real.
The acceleration of the boxes depends on the mass and weight.
we have a mass of 7 and 8 kilograms
if it took 25 N force to move box A, then you would take 25 and multiply by 8 then divide by 2.
It will leave you with 100 N.
finally take the sq rt of 100 to get 10
Given :
Vector A has a magnitude of 63 units and points west, while vector B has the same magnitude and points due south.
To Find :
The magnitude and direction of
a) A + B .
b) A - B.
Solution :
Let , direction in north is given by +j and east is given by +i .
So ,
and 
Now , A + B is given by :


Direction of A+B is 45° north of west .
Also , for A-B :


Direction of A-B is 45° south of west .
( When two vector of same magnitude which are perpendicular to each other are added or subtracted the resultant is always 45° from each of them)
Hence , this is the required solution .
8 tablespoons of water.
2 x 4 = 8
I hope this helps :)