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pickupchik [31]
3 years ago
10

Hi, someone knows how to balance the following equation, and if you can thank you if you can explain how that is done:

Chemistry
1 answer:
kari74 [83]3 years ago
7 0
To begin with, the equation given is not correct.
Correct equation is : CaCO3 + HCl ---> CaCl2 + H2O + CO2
It's CaCl2 not CaCl because Ca has a valency of 2 

    LHS                          RHS
CaCO3 + HCl ---> CaCl2 + H2O + CO2
First of all, to balance the equation you must look at the number of atoms on each side of the equation. 
we have 2 H on the RHS and 1 H on the LHS. So, we put a 2 on the LHS

CaCO3 + 2HCl ---> CaCl2 + H2O + CO2
Check for the LHS: 1 Ca, 1 C, 3 O, 2 H & 2 Cl on the LHS
Now check for the RHS: 1 Ca, 2 Cl, 2 H, 1 C & 3 O

Hope it helped!
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Learn from their experiment and know the possible results from trial and error

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Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb calorimeter has a
dexar [7]

Answer:

Its final temperature is 25.8 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)

When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.

In this case, you know:

  • Q= 14 kJ= 14,000 J
  • c= 3.55  \frac{J}{g*C}
  • m=1.20 kg= 1200 g (1 kg=1000 g)
  • Tfinal= ?
  • Tinitial= 22.5 °C

Replacing:

14,000 J= 3.55 \frac{J}{g*C}*1200 g*(Tfinal-22.5C)

Solving:

\frac{14,000J}{3.55\frac{J}{g*C} *1200 g} =T final - 22.5C

3.3=Tfinal - 22.5 C

3.3 + 22.5=Tfinal

Tfinal= 25.8 °C

<u><em>Its final temperature is 25.8 °C</em></u>

3 0
3 years ago
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5

Explanation:

                     

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MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If .86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent
Katen [24]
HCl:
<span>
m=48,2g
M=36,5g/mol

n = m/M = 48,2g / 36,5g/mol = 1,32mol

1mol          : 4mol
MnO</span>₂        + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol     :  1,32mol
                     limiting reagent 
0,33 will react

HCl is limiting reagent.
6 0
3 years ago
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