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3 years ago

Question 3 (5 points)

Chemistry

1 answer:

Daniel [21]3 years ago

8 0

Answer:

332.918g O2

Explanation:

I'm having some issues with the work however, your final answer should be 332.918g O2

Hope this helped!

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Write the charge balance for a MgSO 4 and NaNO 3 solution that contains H + , OH − , Mg 2 + , HSO − 4 , SO 2 − 4 , MgHSO + 4 , M

irga5000 [103]

Answer :

$MgSO_4$ solution contains $Mg^{2+}$ and $SO_4^{2-}$

$NaNO_3$ solution contains $Na^{+}$ and $NO_3^{-}$

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

The given compounds are, $MgSO_4$ and $NaNO_3$

$MgSO_4$ is an ionic compound which is formed by the combination of $Mg^{2+}$ cation and $SO_4^{2-}$ anion.

and,

$NaNO_3$ is an ionic compound which is formed by the combination of $Na^{+}$ cation and $NO_3^{-}$ anion.

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3 years ago

Tetrachloroethene, C2C14 is a solvent used in many dry cleaning processes.

kondaur [170]

An empirical formula presents the atoms of all the elements with the most simplified whole number ratios. In other words, divide each subscript by their greatest common factor.

The greatest common factor of 2 and 4 is 2.

2/2 = 1

4/2 = 2

So, the empirical formula for tetrachloroethene is CCl₂.

6 0

3 years ago

The element boron exists in nature as two isotopes: 10B has a mass of 10.0129 u, and 11B has a mass of 11.0093 u. The average at

Shalnov [3]

Answer:

Percentage abundance of B 10 is = 20 %

Percentage abundance of B 11 is = 80 %

Explanation:

The formula for the calculation of the average atomic mass is:

$Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})$

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, B 10:

% = x %

Mass = 10.0129 u

For second isotope, B 11:

% = 100 - x

Mass = 11.0093 u

Given, Average Mass = 10.81 u

Thus,

$10.81=\frac{x}{100}\times {10.0129}+\frac{100-x}{100}\times {11.0093}$

$10.0129x+11.0093\left(100-x\right)=1081$

Solving for x, we get that:

x = 20 %

Thus percentage abundance of B 10 is = 20 %

Percentage abundance of B 11 is = 100 - 20 % = 80 %

8 0

3 years ago

Read 2 more answers

How many significant figures are in

Softa [21]

The correct answer would be B: 4.

6 0

2 years ago

What volume will 1.25 liters of carbon dioxide occupy at 50.0°C if the pressure changes from 0.865 atm to 0.820 atm?

Elena-2011 [213]

To solve this we assume that the gas inside the balloon is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 = P2V2

V2 = P1V1 / P2

V2 = 0.865 x 1.25 / 0.820

V2 = 1.32 L

6 0

4 years ago