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Lostsunrise [7]
3 years ago
12

ASAP pls will mark brainiest

Physics
1 answer:
Firdavs [7]3 years ago
7 0

1. False, the relationship between mass and inertia is actually described by Newton's 1st law in which an object will remain still without the tendency to change unless a force is placed upon it.

2. True, Newton did determine a direct relationship between force and mass because the greater the mass, the more force is required.

3. True, any change in velocity is called acceleration, for example, there is deacceleration, zero acceleration, or normal acceleration.

4. True, the greater the force applied to an object, the greater it will accelerate but it also does depend on the mass of an object.

5. False, if the mass of an object is increased, then the given net force will not help it to accelerate.

6. False, a net force of 1N applied to a mass of 1kg does not result in acceleration of 0.5m/s^2 because the net force of a 0.5m/s^2 acceleration is 0.5N.

7. True, the weight of your body does equal mass times gravitational acceleration on earth which is 9.8m/s^2.

8. False, the weight of the 10kg object is heavier than the 5kg object resulting in a slower acceleration.

9. False, the real way to find acceleration is change in velocity over time taken.

10.  False, the acceleration of an object depends on the object's weight.

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A light bulb uses 0.5 amperes from a source of 120 volts. How much power is used by the bulb? 
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8 0
3 years ago
in the diagram, q2 is +34.4*10^-6 C, and q3 is -72.8*10^-6 C. The net force on q2 is 225 N to the right. What is q1? Include the
sesenic [268]

Answer:

  q₁ = -6.54 10⁻⁵ C

Explanation:

Force is a vector quantity, but since all charges are on the x-axis, we can work in one dimension, let's apply Newton's second law

                F = F₁₂ + F₂₃

the electric force is given by Coulomb's law

                F = k q₁q₂ / r₁₂²

let's write the expression for each force

                F₂₃ = k q₂ q₃ / r₂₃²

                F₂₃ = 9 10⁹ 34.4 10⁻⁶ 72.8 10⁻⁶ / 0.1²

                F₂₃ = 2.25 10³ N

               

                F₁₂ = k q₁q₂ / r₁₂²

                F₁₂ = 9 10⁹ q₁ 34.4 10⁻⁶ / 0.1²

                F₁₂ = q₁   3,096 10⁷ N

we substitute in the first equation

                225 = q₁  3,096 10⁷ +2.25 10³

                q₁ = (225 - 2.25 10³) / 3,096 10⁷

                q₁ = -6.54 10⁻⁵ C

4 0
4 years ago
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