Answer:
a. a=33.34ms⁻², V=164.4m/s
Explanation:
Since the dragster started with zero velocity, de determine the acceleration using of the equations of motion.
Below are the data given
Distance, s=404.5m,
time taken,t=4.922secs
Using the equation
S=ut+1/2at²
where u is the initial velocity and u=0
Making the acceleration the subject of the formula, we arrive at
a=2s/t²
a=(2*404.5)/4.922²
a=33.34ms⁻².
To determine the velocity, we use
V=u+at
V=0+33.34ms⁻² *4.922sec
V=164.4m/s
In Electrostatics the electrical force between Two charged objects is inversely Related to the distance of separation between the two objects .
I am pretty sure the answer would be a
Answer:
180.4 m
Explanation:
The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

h = 100 m
x =?
Height formula h:

Time t is cleared:


t = 4.51 sec
Horizontal distance formula x:

x = 40 m / sec x 4.51 sec
x = 180.4 m