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3 years ago

11

In science, a hypothesis must be true. Please select the best answer from the choices provided True or False

2 answers:

hodyreva [135]3 years ago

5 0

Answer:

False

Explanation:

In science, Hypothesis is not an established theory it is just a supposition. It is not necessary that a hypothesis must be true because it is an assumption or an idea which is always tested with an experiment. After carrying out an experiment it can be determined whether the hypothesis is true or false.

Example:

De-Broglie Hypothesis:

De-Broglie gave an hypothesis that light is not a wave nor it posses particle nature but it posses duel nature. According to De-Broglie hypothesis with each moving particle a wave is associated.

But after experiment it is found that with each moving particle a single wave is not associated but a group of wave is associated.

In this way we can say that hypothesis is not always true.

butalik [34]3 years ago

4 0

That's false. A hypothesis may be accurate or full of beans. That's why you do experiments, to test it.

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Illustrated here are three different<br> of carbon. They vary by the number of

Basile [38]

D) isotopes; neutrons

Explanation:

The diagram illustrates the three different isotopes of carbon. They vary by the number of neutrons.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their various nuclei.

Isotopes of elements have the same electronic configuration
They share the same chemical properties
They differ in masses due the number of neutrons they contain.

Learn more:

Isotopes brainly.com/question/1915462

#learnwithBrainly

5 0

3 years ago

Defensive strategies focus on ways to score points against the opposing team.

LenKa [72]

Answer: False

Explanation: Cuz its False, and its false, this message was approved by False.

4 0

3 years ago

You are traveling at 55 mi/h along the x-axis relative to a straight, level road and pass a car that is traveling at 45 mi/h. Th

Alik [6]

Answer:

10 mph

Explanation:

55 - 45 = 10 mph

4 0

1 year ago

A spherical, non-conducting shell of inner radius = 10 cm and outer radius = 15 cm carries a total charge Q = 13 μC distributed

Vaselesa [24]

Answer:

E = 1580594.95 N/C

Explanation:

To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:

$\int EdS=\frac{Q_{in}}{\epsilon_o}$ (1)

dS: differential of the Gaussian surface

Qin: charge inside the Gaussian surface

εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2

The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:

$\int EdS=ES=E(4\pi r^2)$ (2)

Qin is calculate by using the charge density:

$Q_{in}=V_{in}\rho=\frac{4}{3}(r^3-a^3)\rho$ (3)

Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.

The charge density is given by:

$\rho=\frac{Q}{V}=\frac{13*10^{-6}C}{\frac{4}{3}\pi((0.15m)^3-(0.10m)^3)}\\\\\rho=1.30*10^{-3}\frac{C}{m^3}$

Next, you use the results of (3), (2) and (1):

$E(4\pi r^2)=\frac{4}{3\epsilon_o}(r^3-a^3)\rho\\\\E=\frac{\rho}{3\epsilo_o}(r-\frac{a^3}{r^2})$

Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:

$E=\frac{1.30*10^{-3}C/m^3}{3(8.85*10^{-12}C^2/Nm^2)}((0.112m)-\frac{(0.10)^3}{(0.112m)^2})\\\\E=1,580,594.95\frac{N}{C}$

hence, the electric field is 1580594.95 N/C

7 0

2 years ago

The intensity of a certain siren is 0.060 W/m^2 from a distance of 25 meters. What is the intensity of this siren at a distance

Nady [450]

<h2>The intensity of siren is 0.015 W m⁻²</h2>

Explanation:

The intensity of sound is inversely proportional to the square of distance between source and the observer .

Thus Intensity at a distance 25 m is I₁ ∝ $\frac{1}{r_1^2}$ I

Similarly the intensity at a distance 50 m is I₂ ∝ $\frac{1}{r_2^2}$ II

Dividing II by I , we have

$\frac{I_2}{I_1}$ = $\frac{r_1^2}{r_2^2}$ = $\frac{25^2}{50^2}$ = $\frac{1}{4}$

Thus I₂ = $\frac{1}{4}$ x 0.06 = 0.015 W m⁻²

7 0

3 years ago