Answer
given,
Initial speed of the car = 0 m/s
acceleration of car = 2.4 m/s²
Speed of the truck = 15.5 m/s
to car to overtake the truck distance travel by both should be same
distance traveled by the truck
d = 15.5 t
distance traveled by the car
d = u t + 1/2 gt ²
d = 0.5 x 9.8 t²
now, equating both the equations
15.5 t = 4.9 t²
t = 3.163 s
Time taken by car to overtake truck is 3.163 s
distance travel by the car = 15.5 x 3.163
d = 49 m
b) Speed of the automobile
using equation of motion
v = u + at
v = 0 + 2.4 x 3.163
v = 7.59 m/s
Speed of the automobile while crossing truck is equal to v = 7.59 m/s