Question

The amplitude, or magnitude, of a sinusoidal source is the maximum value of the source. What is the amplitude of the voltage source described as v(t)=50cos(2000t−45∘) mVv(t)=50cos⁡(2000t−45∘) mV ?

Answer 1

Answer:

A = 0.05 V

Explanation:

Sinusoidal Functions

A sinusoid or sinusoidal function is a sine or cosine which general equation is

$F(x)=A.sin(wt-\phi)$

Or also

$F(x)=A.cos(wt-\phi)$

Where A is the amplitude or maximum value, w is the angular frequency, t is the time and $\phi$ is the phase shift.

Comparing the given expression with the general formula

$v(t)=50cos(2000t-45^o) mV$

We can establish that A=50 mV = 0.05 V

$A = 0.05\ V$