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timofeeve [1]
3 years ago
9

i throw a tennis ball straight down from the roof of a building 400 meters tall.id it leaves my hand at 10 m/s, how fast will it

be moving when it hits the ground
Physics
1 answer:
Sidana [21]3 years ago
6 0

consider the motion of the tennis ball in downward direction

Y = vertical displacement = 400 m

a = acceleration = acceleration due to gravity = 9.8 m/s²

v₀ = initial velocity of the ball at the top of building = 10 m/s

v = final velocity of the ball when it hits the ground = ?

using the kinematics equation

v² = v²₀ + 2 a Y

inserting the values

v² = 10² + 2 (9.8) (400)

v = 89.11 m/s

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Answer:

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Explanation:

a. Distance is the change in the position of an object.

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b. Since displacement is a vector quantity,

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Substituting the values into the equation, we have;

Q = 202*450*80

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