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mojhsa [17]
2 years ago
11

En una colecta de alimentos no perecibles, lo reunido se clasifica y se ubica en diferentes cajas. En la sección de legumbres ti

enen paquetes de 2,5 kg, 3/4 kg, 1 kg y 7/2 kg, uno de cada uno. ¿Cuántos kilogramos de legumbres se han reunido en total
Mathematics
1 answer:
Klio2033 [76]2 years ago
8 0
4929282828299/829291$
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If 2a+ 2/a =4, what is the value of 2a^2− 2/a^2 ?
aliina [53]

Answer:

0

Step-by-step explanation:

2a+ 2/a =4

Multiply each side by a to clear the fraction

a( 2a+ 2/a) =4*a

Distribute

2a^2 +2 = 4a

Subtract 4a from each side

2a^2 -4a +2 = 4a-4a

2a^2 -4a +2 =0

Divide by 2

2/2 a^2 -4a/2 +2/2 =0/2

a^2 -2a +1=0

Factor

(a-1) (a-1) =0

Using the zero product property

a=1

2a^2 -2/a^2

2(1)^2 -2/1^2

2-2

0

5 0
3 years ago
A cone has a radius of 4 units and a height of 6 units.
Usimov [2.4K]
We know, Volume of a Cylinder = πr² h/3
v = 3.14 * 4² * 6/3
v = 3.14 * 16 * 2
v = 100.48 

In short, Your Answer would be Option B

Hope this helps!
7 0
3 years ago
Read 2 more answers
The product of 1540 and m is a square number. find the smallest possible value of m
aliina [53]

The smallest possible value of m according to the task is; 1/1540.

<h3>What is the smallest possible value of m?</h3>

Since it follows from the task content that the product of 1540 and m is a square number and the smallest possible small number is; 1.

The equation which holds true is; 1540 × m = 1

Consequently, m = 1/1540.

Read more on square numbers;

brainly.com/question/123907

#SPJ1

5 0
2 years ago
Find the 64th term of the following arithmetic sequence.<br><br> 17, 26, 35, 44, ...
goblinko [34]

take the difference

26-17=9

35-26=9

the first term is 17

and the nth term is 64

use the formula

tn=a+(n-1) d

let a be 17

let n be 64

let d be 9

then you substitute

t64=17+(64-1)9

=17+(63)9

=17+567

=584

so the 64th term is 584.

8 0
3 years ago
Help me please and show all work.
Brrunno [24]
Arctan(53/22) = 67.5 degrees
3 0
3 years ago
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