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yuradex [85]
4 years ago
13

F= z-g/n solve for z

Mathematics
1 answer:
Vera_Pavlovna [14]4 years ago
7 0
Z= F+ (g/n) (you’re welcome)
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The first showing is from 2:30 to 4:55. The second showing is from 5:25 to ____. So, the first showing is 2 hours and 25 minutes. The second showing end time had to be around 7:50.
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A 1,000 kg car experiences a net force of 3,500 N from its engine.
Hoochie [10]

Magnitude of the car's acceleration is 3.5 m/s²

<u>Given:</u>

Mass of car = 1,000 kg

Net force applied by car = 3,500 N

<u>Find:</u>

Magnitude of the car's acceleration

<u>Computation: </u>

Net force = Mass × Acceleration

So,

3,500 = 1,000 × Acceleration

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Learn more:

brainly.com/question/12550364?referrer=searchResults

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What is the value of the expression below when x =10 4x+5÷8x+5
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I got 51.25 or 51 1/4
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3 years ago
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The radius of a sphere is increasing at a rate of 4 mm/s. How fast is the volume increasing (in mm^3/s) when the diameter is 60
nexus9112 [7]

Answer:

The volume is increasing at a rate of 1508 cubic millimeters per second when the diameter is 60 mm.

Step-by-step explanation:

Volume of a sphere:

The volume of a sphere is given by the following equation:

V = \frac{4\pi r^3}{3}

In which r is the radius.

Implicit derivatives:

This question is solving by implicit derivatives. We derivate V and r, implicitly as function of t. So

\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}

The radius of a sphere is increasing at a rate of 4 mm/s.

This means that \frac{dr}{dt} = 4

How fast is the volume increasing (in mm^3/s) when the diameter is 60 mm?

This is \frac{dV}{dt} when r = \frac{d}{2} = \frac{60}{2} = 30. So

\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}

\frac{dV}{dt} = 4\pi*(30)^2*4

\frac{dV}{dt} = 1508

The volume is increasing at a rate of 1508 cubic millimeters per second when the diameter is 60 mm.

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3 years ago
Sydney needs to earn $35 so she can buy her father a birthday present. her mom said she can make $6 per hour cleaning around the
Dmitry_Shevchenko [17]

Answer:

if i can be brainliest that would be great

f(x) = x^2+3x-10

f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5

f(x+5) = (x^2+10x+25)+3(x+5)-10

f(x+5) = x^2+10x+25+3x+15-10

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Compare this with x^2+kx+30 and we see that k = 13

Factor and solve the equation below

x^2+13x+30 = 0

(x+10)(x+3) = 0

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x = -10 or x = -3

The smallest zero is x = -10 as its the left-most value on a number line.

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3 years ago
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