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2 years ago

What is the value of x in the solution to the system of linear equations?

Mathematics

1 answer:

Romashka [77]2 years ago

6 0

Answer:

i think it is C

Step-by-step explanation

are the only equivalent answer to y and v

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Evaluate 14 - 2xy when x = -6 and y = 2. -10 28 38 52

kramer

28.
14-2(-6)(2)
14-2(-12)
14- (-24)
14+24
38

5 0

3 years ago

Read 2 more answers

Refer to the accompanying data set and construct a % confidence interval estimate of the mean pulse rate of adult females; the

ivolga24 [154]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval of mean pulse rate for adult female is $71.98 < \mu < 79.88$

The 95% confidence interval of mean pulse rate for adult male is $62.89 < \mu < 70.57$

The correct option is C

Step-by-step explanation:

Generally the sample mean for Male pulse rate is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

= > $\= x_1 = \frac{81 + 74 + \cdots + 59 }{40 }$

= > $\= x_1 = 66.73$

Generally the standard deviation for male pulse rate is mathematically represented as

$\sigma_1 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }$

=> $\sigma_1 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (74 - 66.73 )^2+ \cdot + (59 - 66.73 )^2 }{40-1 } }$

=> $\sigma_1 = 12.24$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma_1 }{\sqrt{n} }$

=> $E = 1.96 * \frac{12.4 }{\sqrt{40} }$

=> $E =3.84$

Generally 95% confidence interval is mathematically represented as

$\= x_1 -E < \mu < \=x_1 +E$

=> $66.73 -3.84 < \mu < 66.73 +3.84$

=> $62.89 < \mu < 70.57$

Generally the sample mean for Female pulse rate is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

= > $\= x_2 = \frac{81 + 94 + \cdots + 73 }{40 }$

= > $\= x_2 = 75.93$

Generally the standard deviation for Female pulse rate is mathematically represented as

$\sigma_2 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }$

=> $\sigma_2 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (94 - 66.73 )^2+ \cdot + (73 - 66.73 )^2 }{40 } }$

=> $\sigma_2 = 12.73$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma_2 }{\sqrt{n} }$

=> $E = 1.96 * \frac{12.73 }{\sqrt{40} }$

=> $E =3.95$

Generally 95% confidence interval is mathematically represented as

$\= x_2 -E < \mu < \=x_2 +E$

=> $75.93 -3.95 < \mu < 75.93 + 3.95$

=> $71.98 < \mu < 79.88$

8 0

2 years ago

A student repeats the process of taking blocks out of a bag and replacing them 100 times. A green block is drawn 67 times. What

Alexeev081 [22]

Using it's concept, it is found that a good estimate for the probability of drawing out a green block from the bag is of 0.67 = 67%.

<h3>What is a probability?</h3>

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, to get a good estimate, we get the probability taking the outcomes from the sample, that is, 67 green blocks out of 100 blocks, hence:

p = 67/100 = 0.67.

A good estimate for the probability of drawing out a green block from the bag is of 0.67 = 67%.

More can be learned about probabilities at brainly.com/question/14398287

5 0

1 year ago

A merchant buys a television for $125 and sells it for $75 more. what is the percent of markup?

guajiro [1.7K]

Since he sold it for $75 more,

% Mark Up = Mark Up/ Cost Price * 100%

% Mark Up = 75 / 125 * 100%

= 0.6 * 100% = 60%

Percent Mark Up = 60%.

Hope this explains it.

4 0

2 years ago

Please help me with this! worth 50 points! I need you to write it for me....

suter [353]

yes because 6 x 2.49=14.49 and that's less than 20 so you'll have a little over 5 dollars to spare.

3 0

2 years ago