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vaieri [72.5K]
3 years ago
15

Suppose that an Egyptian farmer claims to have discovered a linen burial cloth used during Egypt's Middle Kingdom some 4000 year

s ago. Careful analysis shows that the cloth contains 80% of the ^{14}{\rm C} that it is estimated to have originally contained. How old is the cloth?
Physics
1 answer:
enyata [817]3 years ago
7 0

Answer:

the cloth is old by 1,844 years

Explanation:

The computation is shown below:

The half-life of C^(14) is 5730 years

Now

\lambda =1.210 × 10^-4 years^(-1)

Now

N(t) = Ce^{-\lambda\times t}

0.8 \times (N_0) = N_0 \times e^{-\lambda \times t}\\\\ln(0.8) = (-\lambda \times t)\\\\t = \frac{-(ln(0.8))}{\lambda}

\lambda = .000121,

so t = 1844 yrs

hence, the cloth is old by 1,844 years

You might be interested in
Two fans are watching a baseball game from different positions. One fan is located directly behind home plate, 18.3 m from the b
EleoNora [17]

Answer:

  • 0.317 s

Explanation:

distance of fan A = 18.3 m

distance of fan B = 127 m

speed of sound (s) = 343 m/s

What is the time difference between hearing the sound at the two locations?

time (T) = distance / speed

  • time for sound to reach fan A = 18.3 / 343 = 0.053 s
  • time it takes for sound to reach fan B = 127 / 343 = 0.370 s
  • time difference = 0.370 - 0.053 = 0.317 s
5 0
3 years ago
100 POINTS AND BRAINLIEST.
olya-2409 [2.1K]

Answer:

I think the answer must be A.

5 0
3 years ago
A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i
sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, v_{Ci}=25\ m/s

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0
3 years ago
A tissue sample at 275 K is submerged in 2 kg of liquid nitrogen at 70 K for cryopreservation. The final temperature of the nitr
kirill115 [55]

Answer:

The heat capacity of a sample is 37.7 J/K.

Explanation:

Given that,

Submerged temperature of tissue sample = 275 K

Mass of liquid nitrogen= 2 kg

Temperature = 70 K

Final temperature = 75 K

We need to calculate the heat

Using formula of heat

Q=mc(T_{f}-T_{i})

Put the value into the formula

Q=2\times1.039\times10^{3}\times(75-70)

Q=10390\ J

We need to calculate the heat capacity of a sample

Using formula of heat capacity

\Delta S=\dfrac{Q}{T}

Put the value into the formula

\Delta S=\dfrac{10390}{275}

\Delta S=37.7\ J/K

Hence, The heat capacity of a sample is 37.7 J/K.

7 0
3 years ago
Read 2 more answers
to 10 Hz. Superimposed on this signal is 60-Hz noise with an amplitude of 0.1 V. It is desired to attenuate the 60-Hz signal to
givi [52]

Answer:

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

Explanation:

For this case we can use the formula for the Butterworth filter gain given by:

[tec] G = \frac{1}{\sqrt{1 +(\frac{f}{f_c})^{2n}}}[/tex]

Where:

G represent the transfer function and we want that G =0.1 since the desired signal is less than 10% of it's value

f_c = 10 Hz represent the corner frequency

f= 60 Hz represent the original frequency

n represent the filter order and that's the variable that we need to find

G \sqrt{1 +(\frac{f}{f_c})^{2n}} = 1

If we square both sides we got:

G^2 (1+\frac{f}{f_c})^{2n}= 1

We divide both sides by G^2 and we got:

(1+\frac{f}{f_c})^{2n} = \frac{1}{G^2}

Now we can apply log on both sides and we got:

2n ln(1+\frac{f}{f_c}) = ln (\frac{1}{G^2})

And solving for n we got:

n = \frac{ ln (\frac{1}{G^2})}{2ln(1+\frac{f}{f_c})}

And replacing we got:

n = \frac{ln (\frac{1}{0.1^2})}{2ln(1+\frac{60}{10})}

n = \frac{4.60517}{3.8918}=1.18

And since n needs to be an integer the correct answer would be n=2 for the filter order.

7 0
3 years ago
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