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stich3 [128]
3 years ago
7

200mL of 4.98M of sodium chloride solution is added to an additional 532 ml of water what is the final molarity?

Chemistry
1 answer:
ELEN [110]3 years ago
4 0

Answer:

M₂ = 1.9 M

Explanation:

Given data;

Volume of sodium chloride = 200 mL

Molarity of sodium chloride = 4.98 M

Volume of water = 532 mL

Final Molarity = ?

Solution:

M₁V₁ = M₂V₂

M₂ =  M₁V₁ /V₂

M₂ = 4.98 M × 200 mL / 532 mL

M₂ = 996 mL. M /532 mL

M₂ = 1.9 M

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3 years ago
W(OH)2 + 2 HCl → WCl2 + 2 H2O
Afina-wow [57]

The amount of W(OH)2 needed would be 448.126 g

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

W(OH)2 + 2 HCl → WCl2 + 2 H2O

The mole ratio of W(OH)2 to HCl is 1:2

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Equivalent mole of W(OH)2 = 4.11/2

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Mass of 2.06 moles W(OH)2 = 2.06 x 217.855

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More on stoichiometric calculations can be found here: brainly.com/question/8062886

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2 years ago
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Answer:

A

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A CaCl2 solution is given to increase blood levels of calcium. If a patient receives 6.1 mL of a 12 % (m/v) CaCl2 solution, how
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<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

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To learn more about amino acids from the given link:

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