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stich3 [128]
4 years ago
7

200mL of 4.98M of sodium chloride solution is added to an additional 532 ml of water what is the final molarity?

Chemistry
1 answer:
ELEN [110]4 years ago
4 0

Answer:

M₂ = 1.9 M

Explanation:

Given data;

Volume of sodium chloride = 200 mL

Molarity of sodium chloride = 4.98 M

Volume of water = 532 mL

Final Molarity = ?

Solution:

M₁V₁ = M₂V₂

M₂ =  M₁V₁ /V₂

M₂ = 4.98 M × 200 mL / 532 mL

M₂ = 996 mL. M /532 mL

M₂ = 1.9 M

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An air bubble with a radius of 2.5 cm at the bottom of a lake where the temperature is 5.4 0C and the pressure is 3.2atm rises t
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3.8 cm

Explanation:

Given data

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We can find the final volume using the combined gas law.

\frac{P_{1}\times V_{1}}{T_{1}} =\frac{P_{2}\times V_{2}}{T_{2}}\\\frac{3.2atm\times 65cm^{3} }{278.6K} =\frac{1.0atm\times V_{2}}{298.2K}\\V_{2}=223cm^{3}

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finlep [7]

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Explanation:

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3 years ago
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