Answer:
m<MON = 100°
Explanation:
Given:
Area of shaded sector LOM = 2π cm²
NL = 6 cm
Required:
m<MON
Solution:
m<MON = 180° - m<LOM (angles in a straight line)
We don't know m<LOM. Therefore, let's find m<LOM.
Area of a sector = θ/360 × πr²
Area of sector LOM = 2π cm²
r = 3 cm
θ = m<LOM = ?
Plug in the values
2π = m<LOM/360 × π × 3²
2π = m<LOM/360 × 9π
2π = m<LOM × 9π/360
2π = m<LOM × π/40
Multiply both sides by 40
2π × 40 = m<LOM × π
80π = m<LOM × π
Divide both sides by π
80π/π = m<LOM
80 = m<LOM
m<LOM = 80°
✔️m<MON = 180° - m<LOM (angles in a straight line)
Substitute
m<MON = 180° - 80°
m<MON = 100°
I belive the answer to the first one is no I would have to assume a habitual zone is one area on a planet. for example, an air conditioned building vs. the Savvanah dessert. However I am not sure maybe other answers will help more on this one. Sorry.... Earth-like planet would of course need water, plant life, animals, oxygen, fossil fuels etc. A challenge we would face on a travel to another liveable planet: do we have engough transportation? engough fuel to make it? How long can we live on this planet? Who or what else is present here? etc. Yes I do think they should discover a planet with earth like qualities befor investing in tools to get us to them. So money is not wasted. (make sure to put this into your own words )
B. is slightly crooked when pressing the pedals
Body positioning while driving is to maximize control over your vehicle, comfort, and ensure that you don't suffer from back pain due to incorrect sitting posture.
To do this, make sure your bottom is firmly touching the back of the seat. Your seat should be raised high to give yourself maximum visibility and pulled back only enough, so that your knee is still slightly crooked when pressing down on the pedals.
Let me emphasize that you must make sure your seat is pulled far enough forward, so you can fully press the accelerator and the brake pedal, while still having a slight bend in the knee.
Answer:
Explanation:
Alright so the way to do this is to use properties of integrals to make our life easier.
So we have:

So lets break this up into two different integrals that represent the same area.

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

But since we have these values we can say that:
-3 - 2 = -5
Which means that
= -5
So now we can evaluate 
Lets first break up our integrand into two integrals
= 
Now we can evaluate this:
We know that
= -5
So:
where x is evaluated at 4 to 1 so
-15 + 2(3)
So we are left with -15 + 6 = -9