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jekas [21]
2 years ago
9

The watch Bea would like to buy costs $10 less than 2

Mathematics
1 answer:
marin [14]2 years ago
3 0

Answer: Bea has $30 saved

Step-by-step explanation:

Add 10: 50+10=60

Divide by 2: 60/2=30

You might be interested in
Evaluate the following functions at x = 10 q(x)=x^2-2x+2​
Oduvanchick [21]

Answer:

82

Step-by-step explanation:

given:x=10

Evaluating,

(10)²-2(10)+2

=100-20+2

=80+2

=82

Pls mark me brainliest

5 0
3 years ago
Suppose a batch of metal shafts produced in a manufacturing company have a population standard deviation of 1.3 and a mean diame
lbvjy [14]

Answer:

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 208, \sigma = 1.3, n = 60, s = \frac{1.3}{\sqrt{60}} = 0.1678

What is the probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

Lesser than 208 - 0.1 = 207.9 or greater than 208 + 0.1 = 208.1. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.

Lesser than 207.9.

pvalue of Z when X = 207.9. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{207.9 - 208}{0.1678}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

2*0.2743 = 0.5486

54.86% probability that the mean diameter of the sample shafts would differ from the population mean by more than 0.1 inches

6 0
3 years ago
Can someone do #1 and #2 I don't really get the answer. My teacher hasn't explain anything. He just gave us the paper and we got
Elenna [48]
1) f(x) + g(x)

= 7√x + 4 + 2√x - 2

= √x(7 + 2) + 2

= 9√x + 2  [ Final Answer ]

2) f(x) - g(x)

= 7√x + 4 - (2√x - 2)

= 7√x + 4 - 2√x + 2

= √x(7 - 2) + 6

= 5√x + 6   [ Final Answer ]

Hope this helps!
5 0
3 years ago
1) For question 1, use the figure below. a) Are the following polygons similar? Explain. (2 pts) Yes or No b) Assume the polygon
Delvig [45]

Answer: a) Yes b) Polygon ABCD ~ Polygon EFGH c) JKLM is 3x bigger than polygon ABCD

Step-by-step explanation:

(for part c)

JM= 36

AD= 12

36/12= 3

JKLM is 3x bigger than polygon ABCD

3 0
3 years ago
What is the equation, in standard form, of a parabola that models the values in the table?
love history [14]

Answer:

<u>Y=4x^2+3x-6</u>

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u>Y=3x^2+4x-6 for (-2,4)</u>

Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\

This does not give 4 as the answer and is not a solution.

<u>Y=4x^2+3x-6 for (-2,4)</u>

Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\

This does give 4 as the answer and is a possible solution.

<u>Y=4x^2-3x-6 for (-2,4)</u>

Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\

This does not give 4 as the answer and is not a solution.

<u>Y=-4x^2-3x-6 for (-2,4)</u>

Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\

This does not give 4 as the answer and is not a solution.

The only possible solution is <u>Y=4x^2+3x-6</u>

3 0
3 years ago
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