With what I have to say about the way that you are going on the way back and forth between you and me and I have a
The three integers are x, x+2, x+4
5(3x+6)=42+x(x+2)
15x+30=x^2+2x+42
x^2 - 13x +12=0
(x-12)(x-1) = 0
x = 12 or 1
since the integers have to be odd we exclude 12
integers are 1,3,5
