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Julli [10]
4 years ago
9

The thermal conductivity of a solid depends upon the solid’s temperature as k = a T+b where a and b are constants. The temperatu

re in a planar layer of this solid as it conducts heat is given by:a. aT+b= x +C2b. aT+ b = C1x^2 +C2c. aT^2+ bT= C1x+ C2d. aT^2+ +bT= C1x^2+ C2e. None of these

Engineering
1 answer:
Alexandra [31]4 years ago
7 0

Answer:

Answer is Option (e) - None of these

Explanation:

The step by step derivation from the fourier's law of heat conduction is as shown in the attachment below.

Where K = thermal conductivity

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Three methods by which the value of the unknown resistance can be determined​
Contact [7]

Answer:

The Meter bridge is the modification of Wheatstone's network used to determine the value of unknown resistance. The meter bridge consists of a thin, uniform, and homogenous conducting wire AC, rectangular wooden board between two thick L shaped metal strips C1 and C2 as shown in the diagram.

5 0
3 years ago
use engineering judgement to estimate the size of cooling and heating equipment that is needed for a three story, 31,000 square
Blizzard [7]

Answer: operating cost = 22820.736 $

Energy = 32.291 KBtu/sf.

Explanation:

Total heating load is given as = 31000 * 31.25  

 = 968.75* 103 Btu

From the cooling capacity application;

If 1000ftsquare = 2.8 TR

Therefore 30000ftsquare = x

Where x is the total cooling load,

Therefore x = (30000 * 2.8) / 1000

x = 84TR.

Therefore, the total cooling load, x = 84TR

Using conversion factor;

i.e. converting Btu/hr to MBH

1 MBH = 1000 Btu per hour

we have 968.75* 103 Btu/hr = 968.75 MBH

let us proceed.

Estimating the “Annual operating cost” we first calculate the maximum operating cost (Avg/Annum)

For cooling load:

Max. operatn. Cost = 14 * 84 = 1176$

For heating load:

The average heating loading hours = 1000 hrs.

Conversion to Btu/yr gives = 968.75* 103 * 1000  

 = 968.75* 106 Btu/yr.

Conversion of 968.75* 103Btu to Kwh gives  

1Btu = 0.000293

968.75* 103 Btu = 283.84 Kwh  

Therefore, average cost gives;

(8.04/100) $ = 1Kwh

X = 283.84*103

X = 22820.736 $

Operating cost = 22820.736 $

Energy use in KBtu/sf is given as  

E = 968.75* 103 / 30000  

E = 32.291 KBtu/sf.

8 0
4 years ago
A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altitude
Fofino [41]

Answer:

u = 260.22m/s

S_{max} = 1141.07ft

Explanation:

Given

S_0 = 89.6ft --- Initial altitude

S_{16.5} = 0ft -- Altitude after 16.5 seconds

a = -g = -32.2ft/s^2 --- Acceleration (It is negative because it is an upward movement i.e. against gravity)

Solving (a): Final Speed of the rocket

To do this, we make use of:

S = ut + \frac{1}{2}at^2

The final altitude after 16.5 seconds is represented as:

S_{16.5} = S_0 + ut + \frac{1}{2}at^2

Substitute the following values:

S_0 = 89.6ft       S_{16.5} = 0ft     a = -g = -32.2ft/s^2    and t = 16.5

So, we have:

0 = 89.6 + u * 16.5 - \frac{1}{2} * 32.2 * 16.5^2

0 = 89.6 + u * 16.5 - \frac{1}{2} * 8766.45

0 = 89.6 + 16.5u-  4383.225

Collect Like Terms

16.5u = -89.6 +4383.225

16.5u = 4293.625

Make u the subject

u = \frac{4293.625}{16.5}

u = 260.21969697

u = 260.22m/s

Solving (b): The maximum height attained

First, we calculate the time taken to attain the maximum height.

Using:

v=u  + at

At the maximum height:

v =0 --- The final velocity

u = 260.22m/s

a = -g = -32.2ft/s^2

So, we have:

0 = 260.22 - 32.2t

Collect Like Terms

32.2t = 260.22

Make t the subject

t = \frac{260.22}{ 32.2}

t = 8.08s

The maximum height is then calculated as:

S_{max} = S_0 + ut + \frac{1}{2}at^2

This gives:

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 32.2 * 8.08^2

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 2102.22

S_{max} = 89.6 + 260.22 * 8.08 - 1051.11

S_{max} = 1141.0676

S_{max} = 1141.07ft

Hence, the maximum height is 1141.07ft

8 0
3 years ago
Which fact below is NOT one of FoolProof's 4 "Web Facts"?
Deffense [45]

Answer:

E. vitrtually nothing you do on the web is private

3 0
3 years ago
A system consists of a disk rotating on a frictionless axle
kakasveta [241]

The system includes a disk rotating on a frictionless axle and a bit of clay transferring towards it, as proven withinside the determine above.

<h3>What is the angular momentum?</h3>

The angular momentum of the device earlier than and after the clay sticks can be the same.

Conservation of angular momentum the precept of conservation of angular momentum states that the whole angular momentum is usually conserved.

  1. Li = Lf where;
  2. li is the preliminary second of inertia
  3. If is the very last second of inertia
  4. wi is the preliminary angular velocity
  5. wf is the very last angular velocity
  6. Li is the preliminary angular momentum
  7. Lf is the very last angular momentum

Thus, the angular momentum of the device earlier than and after the clay sticks can be the same.

Read more about the frictionless :

brainly.com/question/13539944

#SPJ4

8 0
2 years ago
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