Harmony in music is characterized by _____.

Engineering

2 answers:

stira [4]3 years ago

6 0

Answer:

the vertical relationship of pitches.

Explanation:

Harmony can be defined as the use of simultaneous pitches ( two or more tones and notes) or chords played at the same time together.

Harmony in music is characterized by the vertical relationship of pitches. The three most popular and essential forms of harmony are;

1. Diatonic harmony.

2. Non-diatonic harmony.

3. Atonal harmony.

kotykmax [81]3 years ago

3 0

Question:

1) The horizontal relationship of pitches

2) Only unpleasant sounds

3) The vertical relationship of pitches

4) Only pleasant sounds

Answer:

The correct option is;

3) The vertical relationship of pitches

Explanation:

Harmony, in music is the process whereby individual or sound superposition is evaluated by hearing, that is sounds consisting of frequencies, pitches etc. that occur simultaneously.

Therefore, harmony with regards to musicals considered as vertical because the tones and notes are simultaneously played for which therefore, they are written as vertical music notation.

Therefore, harmony in music is characterized by the vertical relationship of pitches.

You might be interested in

What is the volume of the rectangular prism shown.

Likurg_2 [28]

It would be 72cm bc u need to add up all the line in the back to

7 0

3 years ago

A meter stick can be read to the nearest millimeter and a travelling microscope can be read to the nearest 0.1 mm. Suppose you w

german

Answer: No

Explanation:

Length= 2cm= 20mm

Now meter stick can read to nearest millimeter.

It is given that length is to be measured with a precision of 1% of 20mm= 1/100 * 20= 0.2mm

Since the least count is 1mm of meter stick and precision required is less than that. So, meter stick cannot be used for this, travelling microscope can be used for this as it can read to 0.1mm.

3 0

3 years ago

The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6*g, respectively.

ehidna [41]

Answer:

The speed of shaft is 1891.62 RPM.

Explanation:

given that

Amplitude A= 0.15 mm

Acceleration = 0.6 g

we can say that acceleration= 0.6 x 9.81

$acceleration,a=5.88\ \frac{m}{s^2}$