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3 years ago

Harmony in music is characterized by _____.

Engineering

2 answers:

stira [4]3 years ago

6 0

Answer:

the vertical relationship of pitches.

Explanation:

Harmony can be defined as the use of simultaneous pitches ( two or more tones and notes) or chords played at the same time together.

Harmony in music is characterized by the vertical relationship of pitches. The three most popular and essential forms of harmony are;

1. Diatonic harmony.

2. Non-diatonic harmony.

3. Atonal harmony.

kotykmax [81]3 years ago

3 0

Question:

1) The horizontal relationship of pitches

2) Only unpleasant sounds

3) The vertical relationship of pitches

4) Only pleasant sounds

Answer:

The correct option is;

3) The vertical relationship of pitches

Explanation:

Harmony, in music is the process whereby individual or sound superposition is evaluated by hearing, that is sounds consisting of frequencies, pitches etc. that occur simultaneously.

Therefore, harmony with regards to musicals considered as vertical because the tones and notes are simultaneously played for which therefore, they are written as vertical music notation.

Therefore, harmony in music is characterized by the vertical relationship of pitches.

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A permanent magnet DC motor has an armature resistance of 0.5 Ω and when a voltage of 120 V is applied to the motor it reaches a

BaLLatris [955]

Answer:

12 N-m

Explanation:

The dc motor is operating at 24 V that is its terminal voltage V =24 V

Armature resistance = 0.2 ohm

No load speed = 240 radian /sec

For motor we know that as the motor is on no load so so

Power developed in the motor

Now we know that power = torque× angular speed

3 0

3 years ago

Air enters a compressor operating at steady state at 1.05 bar, 300 K, with a volumetric flow rate of "84" m3/min and exits at 12

Nina [5.8K]

Answer:

W = - 184.8 kW

Explanation:

Given data:

$P_1 = 1.05 bar$

$T_1 = 300K$

$\dot V_1 = 84 m^3/min$

$P_2 = 12 bar$

$T_2 = 400 K$

We know that work is done as

$W = - [ Q + \dor m[h_2 - h_1]]$

for $P_1 = 1.05 bar, T_1 = 300K$

density of air is 1.22 kg/m^3 and $h_1 = 300 kJ/kg$

for $P_2 = 12 bar, T_2 = 400 K$

$h_2 = 400 kj/kg$

$\dot m = \rho \times \dor v_1 = 1.22 \frac{84}{60} =1.708 kg/s$

W = -[14 + 1.708[400-300]]

W = - 184.8 kW

8 0

3 years ago

Why the velocity potential Φ(x,y,z,t) exists only for irrotational flow

Black_prince [1.1K]

Answer:

$\omega_y,\omega_x,\omega_Z$ all are zero.

Explanation:

We know that if flow is possible then it will satisfy the below equation

$\dfrac{\partial u}{\partial x}+\dfrac{\partial v}{\partial y}+\dfrac{\partial w}{\partial z}=0$

Where u is the velocity of flow in the x-direction ,v is the velocity of flow in the y-direction and w is the velocity of flow in z-direction.

And velocity potential function $\phi$ given as follows

$u=-\frac{\partial \phi }{\partial x},v=-\frac{\partial \phi }{\partial y},w=-\frac{\partial \phi }{\partial z}$

Rotationality of fluid is given by $\omega$

$\frac{\partial v}{\partial x}-\frac{\partial u}{\partial y}=\omega_Z$

$\frac{\partial v}{\partial z}-\frac{\partial w}{\partial y}=\omega_x$

$\frac{\partial w}{\partial x}-\frac{\partial u}{\partial z}=\omega_y$

So now putting value in the above equations ,we will find

$\omega =\frac{\partial \phi }{\partial x},u=\frac{\partial \phi }{\partial x},$

$\omega_y=\dfrac{\partial^2 \phi }{\partial z\partial x}-\dfrac{\partial^2 \phi }{\partial z\partial x}$

So $\omega_y$ =0

Like this all $\omega_y,\omega_x,\omega_Z$ all are zero.

That is why velocity potential flow is irroational flow.

5 0

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saw5 [17]

Answer:

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Explanation:

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Goshia [24]

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