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zysi [14]
3 years ago
13

Which fact below is NOT one of FoolProof's 4 "Web Facts"?

Engineering
1 answer:
Deffense [45]3 years ago
3 0

Answer:

E. vitrtually nothing you do on the web is private

You might be interested in
A process engineer performed jar tests for a water in order to determine the optimal pH and dose using alum. A test was conducte
IRINA_888 [86]

Answer:

1) 13 mg/liters

2)  72.22 mg/lit

3)  The Alkanity in raw water is not sufficient enough and the kinds of chemicals needed to enhance its acidity are

  • CaO
  • KOH
  • Na2CO3
  • NaOH
  • CO2
  • NaHCO3

Explanation:

1) plot of turbidity versus dose and optimal dose of Alum ( mg/L )

Optimal dose of Alum = 13 mg/liters from the graph attached below

2) Theoretical amount of alkalinity consumed at the optimal dose can be calculated as follows

Alkanity is due to HCO^-_{3}

given optimal dose of Alum = 13 mg/liters for question 1

I mole of alum = 2 moles of AL(OH)3

666 grams of alum = 2*27 = 54 grams of AL(OH)3

hence 1 mole of AL^{+3}  = (13/54 ) mMole / lit

The  moles of HCO3 = 6 * \frac{13}{54}   because 1 mole of Alum reacts with 6 moles of HC03

[HCO3] as CaCO3 = 6 * (13/54) * 50

                               = 72.22 mg/lit (theoretical amount of alkalinity consumed)

3) The Alkanity in raw water is not sufficient enough and the kinds of chemicals needed to enhance its acidity are

  • CaO
  • KOH
  • Na2CO3
  • NaOH
  • CO2
  • NaHCO3

3 0
3 years ago
In water and wastewater treatment processes a filtration device may be used to remove water from the sludge formed by a precipit
PtichkaEL [24]

Answer:

The volume of sludge after filtration is 0.914 m

Explanation:

Solution

Given that:

We have to find the Volume of sludge after filtration

Now,

The  Sludge concentration is = 32%,

The sludge volume = 100 m,

The sludge concentration after filtration = 35%

Then,

The mass balance equation is stated below

Cin∀in = Cout∀out

Now,

We Solve for ∀out

∀out =Cin∀in/Cout

By substituting the values

∀out = (0.32)(100 m)/(0.35) = 0.914 m

6 0
3 years ago
If you are in a tornado situation, which of the following actions would put you in danger?
anzhelika [568]
Answer: Going outside to film it, not taking cover, trying to run away from the tornado, driving away, etc.

Please mark as brainliest
4 0
3 years ago
Which of the following is most likely to require changes to existing zoning laws?
oksano4ka [1.4K]

Answer:

Adaptive reuse

thats it thankyou

8 0
3 years ago
1. A cylindrical casting is 0.3 m in diameter and 0.5 m in length. Another casting has the same metal is rectangular in cross-se
Lorico [155]

Based on the Chvorinov's rule, the diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the prism casting.

<h3>How to apply the Chvorinov's rule for casting processes</h3>

The Chvorinov's rule is an empirical method to estimate the cooling time of a casting in terms of a <em>reference</em> time. This rule states that cooling time (<em>t</em>) is directly proportional to the square of the volume (<em>V</em>), in cubic meters, divided to the surface area (<em>A</em>), in square meters. Now we proceed to model each casting:

<h3>Cylindrical casting</h3>

t = C · [0.25π · D² · L/(0.5π · D² + π · D · L)]²

t = C · [0.25 · D · L/(0.5 · D + L)]²    (1)

<h3>Prism casting</h3>

t' = C · [3 · T² · L/(6 · T · L + 2 · T · L + 6 · T²)]²

t' = C · [3 · T · L/(8 · L + 6 · T)]²     (2)

<h3>Relationship between the cross sections of both castings</h3>

3 · T² = 0.25π · D²     (3)

Where:

  • <em>t</em> - Cooling time of the cylindrical casting, in time unit.
  • <em>t'</em> - Cooling time of the prism casting, in time unit.
  • <em>C</em> - Cooling factor, in time unit per square meter.
  • <em>D</em> - Diameter of the cylinder, in meters.
  • <em>L</em> - Length of the casting, in meters.
  • <em>T</em> - Width of the cross section of the prism casting, in meters.

If we know that <em>D =</em> <em>0.3 m</em>, then the thickness of the prism casting is:

T = \sqrt{\frac{\pi}{12} }\cdot D

<em>T ≈ 0.153 m</em>

<em />

And (1) and (2) simplified into these forms:

<h3>Cylindrical casting</h3>

t = C · {0.25π · (0.3 m) · (0.5 m)/[0.5 · (0.3 m) + 0.5 m]}²

t = 0.0329 · C     (1b)

<h3>Prism casting</h3>

t' = C · {3 · (0.153 m) · (0.5 m)/[8 · (0.5 m) + 6 · (0.153 m)]}²

t' = 0.00218 · C     (2b)

Lastly we find the <em>percentual</em> difference in the solidification times of the two castings by using the following expression:

<em>r = (</em>1 <em>- t'/t) ×</em> 100 %

<em>r = (</em>1 <em>-</em> 0.00218<em>/</em>0.0329<em>) ×</em> 100 %

<em>r =</em> 93.374 %

The <em>cooling</em> time of the <em>prism</em> casting is 6.626 % of the <em>solidification</em> time of the <em>cylindrical</em> casting. The diference in the <em>solidification</em> times of the two castings is 14.092 times the <em>solidification</em> time of the <em>prism</em> casting. \blacksquare

To learn more on solidification times, we kindly invite to check this verified question: brainly.com/question/13536247

3 0
3 years ago
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