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AlexFokin [52]
3 years ago
13

Solve the given system By graphing if there is no solution or an infinite number of solutions so state you set notation to expre

ss solution sets. { 2x-4y=8, 3X+4y=12 }
WHAT ARE THE POINTS ON A GRAPH? Helppp

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

  (x, y) ∈ { (4, 0) }

Step-by-step explanation:

When the equations are in standard form (or close to it), it is often convenient to graph them using their x- and y-intercepts. The x-intercept is found by setting y=0 and solving for x. The y-intercept is found by setting x=0 and solving for y.

<u>2x -4y = 8</u>

  x-intercept = 8/2 = 4

  y-intercept = 8/-4 = -2

<u>3x +4y = 12</u>

  x-intercept = 12/3 = 4

  y-intercept = 12/4 = 3

__

The two x-intercepts are the same, so that is the solution to the system of equations: (x, y) = (4, 0). There are various ways to write this in set notation. Simply listing the set of solutions is one of them: { (4, 0) }.

_____

<em>Additional comment</em>

Standard form is ax+by=c, where 'a' is positive and a, b, c are mutually prime integers (have no common factors). In the first equation, all of the coefficients are even, so 2 is a common factor. In standard form, that equation would be ...

  x -2y = 4

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The stadium has 53,000 seats seats sell for $42 in section 8 $36 in section B $30 in section C the number of seats in this in se
Zielflug [23.3K]

Answer:

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

Step-by-step explanation:

Total seats = 53,000

Total revenue = 1,997,400

Section A seat = $42

Section B seat = $36

Section C seat = $30

The number of seats in this in section A equals the total number of seats in section BNC

A = B + C

A + B + C = 53,000 (1)

42A + 36B + 30C = 1,997,400 (2)

Substitute A = B + C into (1)

A + B + C = 53,000

B + C + B + C = 53,000

2B + 2C = 53,000

2(B + C ) = 53,000

B + C = 53,000 / 2

= 26,500

B + C = 26,500 (3)

Substitute B + C = 26,500 into (2)

42A + 36B + 30C = 1,997,400

Recall,

A = B + C

42( 26,500) + 36B + 30C = 1,997,400

1,113,000 + 36B + 30C = 1,997,400

36B + 30C = 1,997,400 - 1,113,000

36B + 30C = 884,400. (4)

Multiply (3) by 30

B + C = 26,500 × 30

30B + 30C = 795,000 (5)

36B + 30C = 884,400 (4)

Subtract (5) from (4) to eliminate C

36B - 30B = 884,400 - 795,000

6B = 89,400

B = 89,400/6

= 14,900

B = 14,900

From (3)

B + C = 26,500

C = 26,500 - B

= 26,500 - 14,900

= 11,600

A = B + C

= 14,900 + 11,600

= 26,500

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

8 0
3 years ago
Find the midpoint of the segment with the given endpoint M(-2,1) and N (-3,2)
Aleks04 [339]
(-2,1)
(-2.5,1.5)
(-3,2)
3 0
3 years ago
How can probabilities be used to make fair decisions?
GarryVolchara [31]

he magician starts with the birthday boy and moves clockwise, passing out 100100100100 pieces of paper numbered 1111 through 100100100100. He cycles around the circle until all the pieces are distributed. He then uses a random number generator to pick an integer 1111 through 100100100100, and chooses the volunteer with that number.

Method2: The magician starts with the birthday boy and moves counter-clockwise, passing out 75757575 pieces of paper numbered 1111 through 75757575. He cycles around the circle until all the pieces are distributed. He then uses a random number generator to pick an integer 1111 through 75757575, and chooses the volunteer with that number.

Method 3\: The magician starts with the birthday boy and moves clockwise, passing out 30303030 pieces of paper numbered 1111 through 30303030. He cycles around the circle until all the pieces are distributed. He gives #1111 to the birthday boy, #2222 to the next kid, and so on. He then counts the number of windows in the room and chooses the volunteer with that number.

yes probabilites can be used to make fair ones

thanx

heya

6 0
4 years ago
Please please help me with this ​
iris [78.8K]

Answer:

angle FQE= Minor sector

6 0
3 years ago
Rebotar Inc.makes basketballs.Their fixed costs are $3,450.
melomori [17]

Answer:

<em>Since the profit is positive, Rebotar not only broke even, they had earnings.</em>

Step-by-step explanation:

<u>Function Modeling</u>

The costs, incomes, and profits of Rebotar Inc. can be modeled by means of the appropriate function according to known conditions of the market.

It's known their fixed costs are $3,450 and their variable costs are $12 per basketball produced and sold. Thus, the total cost of Rebotar is:

C(x) = 12x + 3,450

Where x is the number of basketballs sold.

It's also known each basketball is sold at $25, thus the revenue (income) function is:

R(x) = 25x

The profit function is the difference between the costs and revenue:

P(x) = 25x - (12x + 3,450)

Operating:

P(x) = 25x - 12x - 3,450

P(x) = 13x - 3,450

If x=300 basketballs are sold, the profits are:

P(300) = 13(300) - 3,450

P(300) = 3,900 - 3,450

P(300) = 450

Since the profit is positive, Rebotar not only broke even, they had earnings.

8 0
3 years ago
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