Answer:
It is a many-to-one relation
Step-by-step explanation:
Given
See attachment for relation
Required
What type of function is it?
The relation can be represented as:
![\left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dy%5C%5C%20%5C%5C10%5C%5C11%5C%5C4%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Where
and 
Notice that the range has an occurrence of 10 (twice)
i.e.
and 
In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>
Answer:
(f + g)(x) = 3x² + (7/3)x - 8
Step-by-step explanation:
To find (f + g)(x), you need to add both the f(x) and g(x) equations together.
f(x) = x/3 - 2 ..... which is equal to ... f(x) = (1/3)x - 2
g(x) = 3x² + 2x - 6
(f + g)(x) = ((1/3)x - 2) + (3x² + 2x - 6) <----- Add both equations
(f + g)(x) = 3x² + (1/3)x + 2x - 2 - 6 <----- Rearrange (2 = 6/3)
(f + g)(x) = 3x² + (7/3)x - 8 <----- Simplify similar terms
Answer:
4,352
Step-by-step explanation:
17 × 16 × 8 × 2
4352
Josephine travels 32500+78000 yards at 60 mph
=110500yards
=62.78miles
time = distance/spped
time = distance/60
time=62.78/60
time=1.05 (1 hour 5 mins)
Marcus travels 78000(2)(square) +32500(2)
= 84500yards
=48 miles
time = distance/speed
time=48/45
time=1.07 (1 hour 7 mins)
a)Josephine arrives first
b)she arrives earlier by 2 mins.