All categories

4 years ago

Does anyone know this one? Thanks

Physics

1 answer:

Inessa [10]4 years ago

6 0

Answer:

$3.844\,*\,10^5$

So a=3.844 and b=5

Explanation:

Scientific notation requests to write a number using powers of ten as a factor accompanying a real number (a) between 1 and smaller than 10 that contains the digits to exactly represent the original number. So in this case, the number 384,400 can be written as:

$384,400=3.844 \,*\,100,000= 3.844 \,*\,10^5$

with a=3.844, and "5" as the exponent of ten (so b=5)

You might be interested in

A block slides to a stop as it goes 47 m across a level floor in a time of 6.35 s. a) What was the initial velocity? b) What is

UNO [17]

Answer :

(a) The initial velocity is, 14.8 m/s

(b) The acceleration is, $-2.33m/s^2$

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 0 s

u = initial velocity

t = time = 6.35 s

a = acceleration

The equation 1 will be:

$0=u+a(6.35}$

$u=-6.35a$ ..........(2)

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$ ...........(3)

where,

s = distance = 47 m

Now substitute equation 2 in 3, we get:

$47=(-6.35a)\times (6.35)+\frac{1}{2}\times a\times (6.35)^2$

By solving the term, we get:

$a=-2.33m/s^2$

The acceleration is, $-2.33m/s^2$

Now we have to calculate the initial velocity.

Using equation 2, we gte:

$u=-6.35a$

$u=-6.35s\times (-2.33m/s^2)$

$u=14.8m/s$

The initial velocity is, 14.8 m/s

5 0

3 years ago

Momentum data about the same objects in the same closed system is shown below.

nalin [4]

Answer:

the value of x is 3.7 because they are arranged in a particular manner.

6 0

3 years ago

Read 2 more answers

An ultrasound unit is being used to measure a patient's heartbeat by combining the emitted 2.0 MHz signal with the sound waves r

alexandr402 [8]

Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it $f_e$
and we need the Reflected = $f_{r}$
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz = $f_{b}$
so we have:
$f_{e}$ - $f_{r}$ = $f_{b}$
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz = $f_{r}$
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=> $v_{max}$ = (lambda)( $f_{r}$
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the $v_{max}$ is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day

8 0

4 years ago

Which of these objects would be most likely to create this sound wave?

babunello [35]

Answer: It’s C.

Explanation:

4 0

4 years ago

Read 2 more answers

Echoic sensory memory is used when a lightning bolt flashes across the sky.

Ahat [919]

If the statement above answers whether the statement is true or false, then the answer is false. It is not true that the echoic sensory memory is used when a lightning bolt flashes across the sky because it does not have that kind of capacity. The echoic sensory memory is the one responsible for the auditory information.

6 0

3 years ago

Read 2 more answers