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2 years ago

As it heats, does fluid rise or compact s

Physics

2 answers:

vovangra [49]2 years ago

5 0

Answer: The fluid would rise.

ollegr [7]2 years ago

4 0

The cooler fluid then replaces the warm rising fluid and a current is set up (see illustration above). So, where gravity is a factor, such as here on earth, the natural fluid motion moves the heated, less dense fluid up and the cooler, more compact fluid down.
Hope that helps

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The temperature of a sample of silver increased by 24.0 °C when 269 J of heat was applied. What is the mass of the sample?

statuscvo [17]

Answer:

Mass of the silver will be equal to 46.70 gram

Explanation:

We have given heat required to raise the temperature of silver by 24°C is 269 J , so $\Delta T=24^{\circ}C$

Specific heat of silver = 0.240 J/gram°C

We have to find the mass of silver

We know that heat required is given by

$Q=mc\Delta T$ , here m is mass, c is specific heat of silver and $\Delta T$ is rise in temperature

So $269=m\times 0.240\times 24$

m = 46.70 gram

So mass of the silver will be equal to 46.70 gram

3 0

2 years ago

air passing over an airplanes wing travels ,and therefore exerts pressure.than air traveling beneath the wing.

pickupchik [31]

Bernoulli's principle of laminar/lamellar air flow, I think. High flow speed = low pressure, low flow speed = high pressure I think. So, the wings/aerofoils are designed to induce a low pressure on the top side of the wing and a high pressure on the underside of the wing, thus producing an "aerodynamic upthrust" (a static upthrust comes from an object in water via Archimedes) and LIFT.

Two "particles" of air one going topside and the other underside meet again at the end of their motion across the wing. So, top side has to travel faster than bottom side. So top side has a lower "dynamic pressure" than underside.

And all that for 5 points ????????? (If I'm right, of course ... )

5 0

2 years ago

Helppp meeee

worty [1.4K]

T = (v-0)/a
t = (45.5)/(9.8)
= 4.64m/s.

hope this helps :)

7 0

2 years ago

Estimate the inductance L of a coil that is 12 cm long, made of about 235 copper-wire turns and a diameter of about 1.7 cm. Show

ANTONII [103]

Answer:

Inductance as calculated is 13.12 mH

Solution:

As per the question:

Length of the coil, l = 12 cm = 0.12 m

Diameter, d = 1.7 cm = 0.017 m

No. of turns, N = 235

Now,

Area of cross-section of the wire, A = $\frac{\pi d^{2}}{4} = \frac{\pi \times 0.017^{2}}{4} = 2.269\times 10^{- 4}\ m^{2}$

We know that the inductance of the coil is given by the formula:

$L = \frac{mu_{o}AN^{2}}{l} = \frac{4\pi \times 10^{- 7}\times 2.269\times 10^{- 4}\times 235^{2}}{0.12} = 1.312\times 10^{- 4}\ H = 13.12\ mH$

4 0

2 years ago

Which product of nuclear decay has mass but no charge?

Tom [10]

Neutrons have a zero charge but consist of mass.

3 0

2 years ago