The eaths radius is the correct answer, if you need proof look at nasa's website
Since the electric field between the plates is constant, If the two plates are brought closer together, the potential difference between the two plates decreases
The relation between potential difference and the electric field is given by ΔV = E.d
Since the electric field is maintained constant, the potential difference is directly inversely proportional to the distance between the plates.
The potential difference between the plates will therefore likewise decrease if the distance between the plates is reduced, we will state in this case.
The energy required to move a unit charge, or one coulomb, from one point to the other in a circuit is measured as the potential difference between the two points. Potential difference is measured in volts or joules per coulomb.
Refer to more about the potential difference here
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Answer:
s
Explanation:
From the question we are told that
The outer ring with a radius of 30 m
inner Gravity Approximately 9.80 m/s'
Outer Gravity Approximately 5.35 m/s.
Generally the equation for centripetal force is given mathematically as
Centripetal acceleration enables Rotation therefore?
![\omega ^2 r =Angular\ acc](https://tex.z-dn.net/?f=%5Comega%20%5E2%20r%20%3DAngular%5C%20acc)
Considering the outer ring,
![\omega ^2 r = 9.8](https://tex.z-dn.net/?f=%5Comega%20%5E2%20r%20%3D%209.8)
![\omega ^2= \frac{9.8}{30}](https://tex.z-dn.net/?f=%5Comega%20%5E2%3D%20%5Cfrac%7B9.8%7D%7B30%7D)
![\omega = \sqrt{\frac{9.8}{30}}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Csqrt%7B%5Cfrac%7B9.8%7D%7B30%7D%7D)
![\omega= 0.571 rad/s](https://tex.z-dn.net/?f=%5Comega%3D%200.571%20rad%2Fs)
Therefore solving for Period T
Generally the equation for solving Period T is mathematically given as
![T= \frac{2\pi}{\omega}](https://tex.z-dn.net/?f=T%3D%20%5Cfrac%7B2%5Cpi%7D%7B%5Comega%7D)
![T= \frac{2\pi}{0.571 rad/s}](https://tex.z-dn.net/?f=T%3D%20%5Cfrac%7B2%5Cpi%7D%7B0.571%20rad%2Fs%7D)
s