Answer:
a) 12.74 V
b) Two pairs of diode will work only half of the cycle
c) 8.11 V
d) 8.11 mA
Explanation:
The voltage after the transformer is relationated with the transformer relationshinp:
the peak voltage before the bridge rectifier is given by:
The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:
As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.
The averague voltage on a full wave rectifier is given by:
Using Ohm's law:
- A sketch of the junction between one chairlift and two runs is shown in the image attached below.
- For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.
<h3>What is Kirchhoff's loop rule?</h3>
Kirchhoff's loop rule is also referred to as Kirchhoff's second law or Kirchhoff's voltage law, and it states that the algebraic sum of all the electric potential differences around any closed loop is equal to zero.
<h3>How to connect two runs in series?</h3>
Since the chairlifts are analogous to batteries, and the runs are analogous to resistors, the two runs would represent resistors that are connected in series with the lift, which represents the battery. Similarly, these three runs can also be connected in parallel by altering the positions of the runs with the battery.
For this ski resort, it ultimately implies that the total number of lifts that are used in any closed loop would be equal to zero in accordance with Kirchhoff's loop rule.
Read more on Kirchhoff's loop rule here: brainly.com/question/15003023
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Answer:
The spacing between the slits is 
Explanation:
From the question we are told that
The wavelength of the light is 
The distance of the slit from the screen is 
The number of bright fringe is 
The length the fringes span is 
The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as
Where d is the distance between the slits
is the fringe width which can also be evaluated as
Substituting values
Making d the subject of formula in the above equation
Substituting values
