Answer:
energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms.
Answer:
Lf=3.34×105 L f = 3.34 × 10 5 J/kg
Explanation:
It's pretty simple, um, enjoy.
Answer:
The force that pulls the car down is Wₓ = 14052.6 N and the one that pushes the car up is F = 26552.6 N
Explanation:
For this exercise we will use Newton's second law, let's set a reference system where the x axis is parallel to the plane, in the adjoint we can see the forces in the system.
sin 35 = Wₓ / W
cos 35 = W_y / W
Wₓ = W sin 35
W_y = W cos 35
Wₓ = 2500 9.8 sin 35
Wₓ = 14052.6 N
let's write the equations for each axis
and
Y axis
N-W_y = 0
N = W_y
X axis
F -Wₓ = m a
F = Wₓ + m a = mg sin 35 + m a
F = m (a + g sin 35)
let's calculate
F = 2500 (5 + 9.8 sin 35)
F = 26552.6 N
The force that pulls the car down is Wₓ = 14052.6 N and the one that pushes the car up is F = 26552.6 N
<h2>
Answer:</h2>
1.77V
<h2>
Explanation:</h2>
The electromotive force voltage (E) in a cell, is related to the lost voltage (
) and the terminal voltage (
) as follows;
E = -
Where;
The lost voltage () is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e
= I x r
<em>Substitute </em><em> = I x r into equation (i) as follows;</em>
E = - (I x r) ----------------------(ii)
<em>According to the question;</em>
E = 1.54V
I = 2.15A
r = 0.105Ω
<em>Substitute these values into equation(ii) as follows;</em>
1.54 = - (2.15 x 0.105)
1.54 = - (0.22575)
1.54 = - 0.22575
<em>Solve for </em><em>;</em>
= 1.54 + 0.22575
= 1.54 + 0.22575
= 1.77V
Therefore, the terminal voltage of the cell is 1.77V
The sun <u><em>appears</em></u> brighter than any other star.
(It isn't really, but it looks that way because it's much much much much much much closer to us than any other star.)
