3 years ago

Which of the following examples illustrates static friction?

Physics

1 answer:

vivado [14]3 years ago

6 0

Answer:

A box sits stationary on a ramp

Explanation:

Static friction is a force which keeps an object at rest as it is in the case of the box. It has to be overcome for the object to be set into motion.

Static force of friction is calculated as follows:

F= μη

F is static force of friction.

μ is the coefficient of static friction.

η is the normal force.

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Which of the following would cause the greatest decrease in gravitational force between the earth and the moon? an increase in t

Sphinxa [80]

<span>a decrease in the distance between the earth and the moon</span>

8 0

3 years ago

Speed (mph) 58 72 55 65 70 81 66 What car goes the fastest? Put the car speed in order, from fastest to slowest miles per hour.

RoseWind [281]

Answer:

The answer to your question is letter B

Explanation:

Data

Order from fastest to slowest speed

58 72 55 65 70 81 66

The fastest is 81, then, 72, 70, then, 66, 65 finally 58 and 55

The correct order

81 mi/h, 72 mi/h, 70 mi/h, 66 mi/h, 65 mi/h, 58 mi/h, 55 mi/h

The other options are from slowest to fastest or a different order.

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3 years ago

A mail carrier leaves the post ofﬁce and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00

den301095 [7]

Answer:

$\theta=7^o$

Explanation:

<u>Displacement</u>

It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.

The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

$\vec r_1=\ km$

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

$\vec r_2=\ km=\ km$

Finally, he drives 9.5 km 35° north of east.

$\vec r_3=\ km=\ km$

The total displacement is

$\vec r_t=\ km+\ km+\ km$

$\vec r_t=\ km$

The direction can be calculated with

$\displaystyle tan\theta=\frac{1.39}{11.28}=0.1232$

$\boxed{\theta=7^o}$

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3 years ago

a 150 kg object takes 1.5 minutes to travel a 2,500 meter straight path. It begins the trip traveling 120 m/s and decelerates to

Firlakuza [10]

Answer:

-1.11 m/s²

Explanation:

v = at + v₀

Given v = 20 m/s, v₀ = 120 m/s, and t = 1.5 min = 90 s:

20 m/s = a (90 s) + 120 m/s

a = -1.11 m/s²

7 0

2 years ago

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