Which of the following examples illustrates static friction?
1 answer:
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Initially, the velocity vector is . At the same height, the x-value of the vector will be the same, and the y-value will be opposite (assuming no air resistance). Assuming perfect reflection off the ground, the velocity vector is the same. After 0.2 seconds at 9.8 seconds, the y-value has decreased by
, so the velocity is
.
Converting back to direction and magnitude, we get
Answer:
The range of the bullet is 0.435 kilometers.
Explanation:
According to the problem, maximum height is equal to the range of the bullet. That is:
Where:
- Range of the bullet, measured in meters.
- Maximum height of the bullet, measured in meters.
By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:
Where:
- Kinetic energy at point 1, measured in joules.
- Gravitational potential energy at point 2, measured in joules, and:
Where:
- Mass of the bullet, measured in kilograms.
- Gravitational constant, measured in meters per square second.
The maximum height is now cleared:
If ,
and
, the maximum height is now computed:
Lastly, the range of the bullet is 0.435 kilometers.